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You are given a triangle that has sides of 66cm, 73cm, and 94cm. One of the angles is right-angled (meaning that it is possible by trial and error to calculate what each of the angles are). Inside this triangle is a square, so that three corners are in contact with the lines bounding the triangle. One of the sides or the square, which we shall now dub z, is also tangent to a circle, with a radius such that the centre of the circle lies along the side of the triangle with length 73cm. You are also given a regular octagon, which you are told is the same area as the total are of the circle and triangle if they are taken together (i.e. the overlapping area is not counted twice), and one side of this octagon forms another side of equal length belonging to a second square. The area of this square is dubbed x.
Question 1 Give the value, to three significant figures, of x.
Question 2 An isosceles triangle is drawn so that it has the same area as the above square (i.e. x), and with two sides that are equal to the square root of x (henceforth dubbed y). What is the length of the third side?
This is a question that even historians couldn't solve.
Question 3 Prove that the triangle above exists.
This is one of the worlds hardest unsolved math problem.
Heres where I got the questions from. http://uncyclopedia.wikia.com/wiki/The_World's_Hardest_Maths_Problems
wow just wow
my dad is a math teacher in asu and he cant do it
Whoever tries earns a medal!
my dad tried???
okey. heres a medal.
this is a message to any other people who come You will earn a medal if you try to solve this problem.
Anyone dares to try to solve this question?
sqrt(66^2+73^2) = 98.41239... therefore the triangle is not a rt triangle
and other than that, i have no idea what the question is asking for