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anonymous

  • one year ago

Find the arc lenght

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  1. anonymous
    • one year ago
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    |dw:1442618898018:dw|

  2. anonymous
    • one year ago
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    |dw:1442618963230:dw|

  3. anonymous
    • one year ago
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    |dw:1442619001455:dw|

  4. anonymous
    • one year ago
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    this is where i got stuck..

  5. amistre64
    • one year ago
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    its a good place to get stuck at for sure ... a trig sub might be a good shot, maybe.

  6. anonymous
    • one year ago
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    im using this formula..|dw:1442619138404:dw|

  7. anonymous
    • one year ago
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    we havnt gotten into using trigs yet...

  8. anonymous
    • one year ago
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    my professor said something about making whats inside the sqrt to a perfect square to be able to cancel the sqrt, but i dont see how i can make it that way...

  9. amistre64
    • one year ago
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    4x^2 + kx + 1 (2x+1)^2 seems good 4x^2 + 1 + (4x-4x) = (2x+1)^2 -4x

  10. amistre64
    • one year ago
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    i dont believe that you can just 'make' something into a perfect square, you can rewrite it so that it 'contains' a perfect square

  11. amistre64
    • one year ago
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    if u = 2x+1, du=2dx and x=(u-1)/2 (2x+1)^2 -4x u^2 -4(u-1)/2 u^2 -2u +2 is still not a perfect square

  12. amistre64
    • one year ago
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    http://www.wolframalpha.com/input/?i=integrate+sqrt%281%2B4x^2%29+dx notice that the wolfs integral isnt that pretty without knowing some hypertrigs

  13. anonymous
    • one year ago
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    well thanks for the help ill email my professor.. so she can solve it lol

  14. amistre64
    • one year ago
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    if y=t, then x^2 = t, and x=sqrt(t) y' = 1, x' = 1/(2sqrt(t)) y'^2 = 1, x'^2 = 1/(4t) but that doesnt make for a pretty integral either

  15. anonymous
    • one year ago
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    omg i have tried to solve this problem over 100 times and guess what i read the question wrong. the questions sais to use a graphing utility to evaluate it

  16. anonymous
    • one year ago
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    but again using in getting this https://www.wolframalpha.com/input/?i=arc+length+of+y%3Dsqrt%281%2B4x^2%29+from+x%3D0+to+3

  17. anonymous
    • one year ago
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    when the the answer is 9.747

  18. amistre64
    • one year ago
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    arclength of y=x^2

  19. amistre64
    • one year ago
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    https://www.wolframalpha.com/input/?i=arc+length+of+y%3Dx^2+from+x%3D0+to+3

  20. wmj259
    • one year ago
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    Are you not able to use the ArcLength formula of vectors to solve this?

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spraguer (Moderator)
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is replying to Can someone tell me what button the professor is hitting...

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