anonymous
  • anonymous
Find the arc lenght
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
|dw:1442618898018:dw|
anonymous
  • anonymous
|dw:1442618963230:dw|
anonymous
  • anonymous
|dw:1442619001455:dw|

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anonymous
  • anonymous
this is where i got stuck..
amistre64
  • amistre64
its a good place to get stuck at for sure ... a trig sub might be a good shot, maybe.
anonymous
  • anonymous
im using this formula..|dw:1442619138404:dw|
anonymous
  • anonymous
we havnt gotten into using trigs yet...
anonymous
  • anonymous
my professor said something about making whats inside the sqrt to a perfect square to be able to cancel the sqrt, but i dont see how i can make it that way...
amistre64
  • amistre64
4x^2 + kx + 1 (2x+1)^2 seems good 4x^2 + 1 + (4x-4x) = (2x+1)^2 -4x
amistre64
  • amistre64
i dont believe that you can just 'make' something into a perfect square, you can rewrite it so that it 'contains' a perfect square
amistre64
  • amistre64
if u = 2x+1, du=2dx and x=(u-1)/2 (2x+1)^2 -4x u^2 -4(u-1)/2 u^2 -2u +2 is still not a perfect square
amistre64
  • amistre64
http://www.wolframalpha.com/input/?i=integrate+sqrt%281%2B4x^2%29+dx notice that the wolfs integral isnt that pretty without knowing some hypertrigs
anonymous
  • anonymous
well thanks for the help ill email my professor.. so she can solve it lol
amistre64
  • amistre64
if y=t, then x^2 = t, and x=sqrt(t) y' = 1, x' = 1/(2sqrt(t)) y'^2 = 1, x'^2 = 1/(4t) but that doesnt make for a pretty integral either
anonymous
  • anonymous
omg i have tried to solve this problem over 100 times and guess what i read the question wrong. the questions sais to use a graphing utility to evaluate it
anonymous
  • anonymous
but again using in getting this https://www.wolframalpha.com/input/?i=arc+length+of+y%3Dsqrt%281%2B4x^2%29+from+x%3D0+to+3
anonymous
  • anonymous
when the the answer is 9.747
amistre64
  • amistre64
arclength of y=x^2
amistre64
  • amistre64
https://www.wolframalpha.com/input/?i=arc+length+of+y%3Dx^2+from+x%3D0+to+3
wmj259
  • wmj259
Are you not able to use the ArcLength formula of vectors to solve this?

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