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anonymous
 one year ago
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anonymous
 one year ago
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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I think the right answer to this is .12

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2So for linear approximation we use ummm...\[\large\rm f(x)\approx f(x_o)+\color{orangered}{f'(x_o)(xx_o)}\]Something like that, ya? Where the orange stuff is our error. Wait.. is that the error? Hmmm thinking

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Im not sure this problem is very confusing

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2Yes it is +_+ So the error in the output \(\large\rm \Delta y \) ummm... ya ya ya, should be \(\large\rm f'(x_o)\color{green}{\Delta x}\), where Delta x is the distance between our base point x_o and x. \(\large\rm \Delta y\approx f'(x_o)\color{green}{(xx_o)}\) So our base point is x=1. And we're drifting 0.001 away from that. \[\large\rm \Delta y\approx f'(1)(0.001)\]

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2Were you able to come up with a formula for Surface Area of a cube? :) And its derivative?

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2Take a cube, call the side length x. Since it's a cube, all side lengths are the same. The area of one face will be x*x, ya? So the total surface area will be the area of all 6 panels of the cube. \(\large\rm A=6x^2\)

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2Wait wait, then how were you able to come up with .12? LOL Just straight up guessing? >.< Buhaha, Cam cam, come on!!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Haha yes it was a guess but it made sense

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2So your derivative is \(\large\rm A'=12x\). Mmm k.

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2And your error approximation for the output \(\large\rm \Delta y\) is going to be\[\large\rm =A'(x_o)\Delta x\]Our base point is x=1. And our delta is the distance between the x's, 0.001.

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2\[\large\rm =A'(1)(0.001)=?\]

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2What? 0_o Plug 1 into A'(x) and then multiply that value by 0.001

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2Hmm that's not what I'm getting.. lemme see..

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2\[\large\rm =\color{orangered}{A'(1)}(0.001)=\color{orangered}{12(1)}(0.001)=12(0.001)=0.012\]

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2Is that one of our options? :o Hopefully we're doing this right <.<

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2What do the other options look like? XD

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0.02 .003 and none of the above

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2Hmm :p @ganeshie8 @dan815

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ill just put in .12 and hope thats the answer

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thank you for the help!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Its okay thanks for the help!!
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