moonlight93
  • moonlight93
a solution of 1.15g of solute dissolved in 25.0 mL of H2O at 25 degree C has a boiling point of 100.85 degree C. What is the molar mass of the solute if it is a nonvolatile nonelectrolyte and the solution behaves ideally ( s of H2O at 25 degree C = 0.997 g/mL) ? I need help with this problem! what formulas should I use, and how can I start with this? Thank you for any help.
Chemistry
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SOLVED
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katieb
  • katieb
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surry99
  • surry99
Look up boiling point elevation
surry99
  • surry99
you will find a formula that will get you started.
moonlight93
  • moonlight93
can you check my work, and my final answer please. (100.85 - 100.00) °C / (0.512 °C/m) = 1.660 m (1.660 mol/kg) x (25.0 mL x (0.997 g/mL) / (1000 g/kg)) = 0.04138 mol (1.15 g) / (0.04138 mol) = 25.27 g/mol

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moonlight93
  • moonlight93
@surry99
surry99
  • surry99
Method looks fine, math looks good as well.
moonlight93
  • moonlight93
thank you
moonlight93
  • moonlight93
the final answer should be 28

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