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moonlight93

  • one year ago

a solution of 1.15g of solute dissolved in 25.0 mL of H2O at 25 degree C has a boiling point of 100.85 degree C. What is the molar mass of the solute if it is a nonvolatile nonelectrolyte and the solution behaves ideally ( s of H2O at 25 degree C = 0.997 g/mL) ? I need help with this problem! what formulas should I use, and how can I start with this? Thank you for any help.

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  1. surry99
    • one year ago
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    Look up boiling point elevation

  2. surry99
    • one year ago
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    you will find a formula that will get you started.

  3. moonlight93
    • one year ago
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    can you check my work, and my final answer please. (100.85 - 100.00) °C / (0.512 °C/m) = 1.660 m (1.660 mol/kg) x (25.0 mL x (0.997 g/mL) / (1000 g/kg)) = 0.04138 mol (1.15 g) / (0.04138 mol) = 25.27 g/mol

  4. moonlight93
    • one year ago
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    @surry99

  5. surry99
    • one year ago
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    Method looks fine, math looks good as well.

  6. moonlight93
    • one year ago
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    thank you

  7. moonlight93
    • one year ago
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    the final answer should be 28

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