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korosh23
 one year ago
Precalculus 12 question!
korosh23
 one year ago
Precalculus 12 question!

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korosh23
 one year ago
Best ResponseYou've already chosen the best response.0I know about reflections and transformations. But, I do not know what is the original quadrant for the y= f(x)

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4dw:1442628165997:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4#15 a) y = f(x) is in Q4 completely dw:1442628178659:dw so draw any function that is just in the lower right quadrant

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4since y = f(x), and because we go from f(x) to f(x), this means that the y coordinates will flip in sign. If they are negative, they become positive, and vice versa

korosh23
 one year ago
Best ResponseYou've already chosen the best response.0How shoud I know if it is in Quadrant 4?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4it's given in the instructions

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4for example, if we know (2,10) lies on f(x), then (2,10) lies on f(x). All I did was flip the sign of the y coordinate dw:1442628273298:dw

korosh23
 one year ago
Best ResponseYou've already chosen the best response.0it would become quadrant 1?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4imagine doing this for EVERY point on f(x) dw:1442628349334:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4yeah it will all be in Q1 dw:1442628394556:dw

korosh23
 one year ago
Best ResponseYou've already chosen the best response.0yes. Vertical reflection

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4yep reflection over the x axis

korosh23
 one year ago
Best ResponseYou've already chosen the best response.0I can do the rest from now on. Thank you for your help @jim_thompson5910 :)
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