korosh23
  • korosh23
Pre-calculus 12 question!
Mathematics
  • Stacey Warren - Expert brainly.com
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katieb
  • katieb
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korosh23
  • korosh23
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korosh23
  • korosh23
I know about reflections and transformations. But, I do not know what is the original quadrant for the y= f(x)
jim_thompson5910
  • jim_thompson5910
|dw:1442628165997:dw|

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jim_thompson5910
  • jim_thompson5910
#15 a) y = f(x) is in Q4 completely |dw:1442628178659:dw| so draw any function that is just in the lower right quadrant
jim_thompson5910
  • jim_thompson5910
since y = f(x), and because we go from f(x) to -f(x), this means that the y coordinates will flip in sign. If they are negative, they become positive, and vice versa
korosh23
  • korosh23
How shoud I know if it is in Quadrant 4?
jim_thompson5910
  • jim_thompson5910
it's given in the instructions
korosh23
  • korosh23
Oh. Right
jim_thompson5910
  • jim_thompson5910
for example, if we know (2,-10) lies on f(x), then (2,10) lies on -f(x). All I did was flip the sign of the y coordinate |dw:1442628273298:dw|
korosh23
  • korosh23
ok
korosh23
  • korosh23
it would become quadrant 1?
jim_thompson5910
  • jim_thompson5910
imagine doing this for EVERY point on f(x) |dw:1442628349334:dw|
jim_thompson5910
  • jim_thompson5910
yeah it will all be in Q1 |dw:1442628394556:dw|
korosh23
  • korosh23
yes. Vertical reflection
jim_thompson5910
  • jim_thompson5910
yep reflection over the x axis
korosh23
  • korosh23
I can do the rest from now on. Thank you for your help @jim_thompson5910 :)
jim_thompson5910
  • jim_thompson5910
no problem

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