what is the equation of the line that passes through the points (3,4) and (-1,5)

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what is the equation of the line that passes through the points (3,4) and (-1,5)

Mathematics
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slope of the line = \[\frac{y2-y1}{x2-x1}\]
let m be the slope of a line \[m=\frac{y2-y1}{x2-x1}\] y=mx <--- is that line that goes through the origin you can displace that line by some y value and x so that its not going through the origin with that slope but its going through one of your points
|dw:1442638013903:dw|

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Other answers:

you can move the line by having a y intercept with the same slope?
well thats an idea
so you're saying we should find this point |dw:1442638180453:dw|
lets say that value is b
y=mx+b shifts the y=mx by b units up as we are adding b to every value on the line now
|dw:1442638272009:dw|
having a line equation means your point satisfies the equation you have for your line
y=mx+b so when you plug in your point (3,4) oor when you plug in your point (-1,5) it satisfies the equation y=mx+b
so when you plug in 3,4 4=m*3+b when you plug in -1,5 5=m*-1+b
4=-3/4+b and 5=1/4+b?
find the slope by the formula y2-y1/x2-x1
5-4/-1-3=-1/4
now equation of the line- y-y1=m(x-x1) y-4=-1/4 (x-3)
4y+x=19

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