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EXOEXOEXO

  • one year ago

what is the equation of the line that passes through the points (3,4) and (-1,5)

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  1. dan815
    • one year ago
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    slope of the line = \[\frac{y2-y1}{x2-x1}\]

  2. dan815
    • one year ago
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    let m be the slope of a line \[m=\frac{y2-y1}{x2-x1}\] y=mx <--- is that line that goes through the origin you can displace that line by some y value and x so that its not going through the origin with that slope but its going through one of your points

  3. dan815
    • one year ago
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    |dw:1442638013903:dw|

  4. EXOEXOEXO
    • one year ago
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    you can move the line by having a y intercept with the same slope?

  5. dan815
    • one year ago
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    well thats an idea

  6. dan815
    • one year ago
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    so you're saying we should find this point |dw:1442638180453:dw|

  7. dan815
    • one year ago
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    lets say that value is b

  8. dan815
    • one year ago
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    y=mx+b shifts the y=mx by b units up as we are adding b to every value on the line now

  9. dan815
    • one year ago
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    |dw:1442638272009:dw|

  10. dan815
    • one year ago
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    having a line equation means your point satisfies the equation you have for your line

  11. dan815
    • one year ago
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    y=mx+b so when you plug in your point (3,4) oor when you plug in your point (-1,5) it satisfies the equation y=mx+b

  12. dan815
    • one year ago
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    so when you plug in 3,4 4=m*3+b when you plug in -1,5 5=m*-1+b

  13. EXOEXOEXO
    • one year ago
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    4=-3/4+b and 5=1/4+b?

  14. madhu.mukherjee.946
    • one year ago
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    find the slope by the formula y2-y1/x2-x1

  15. madhu.mukherjee.946
    • one year ago
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    5-4/-1-3=-1/4

  16. madhu.mukherjee.946
    • one year ago
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    now equation of the line- y-y1=m(x-x1) y-4=-1/4 (x-3)

  17. madhu.mukherjee.946
    • one year ago
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    4y+x=19

  18. madhu.mukherjee.946
    • one year ago
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    @EXOEXOEXO

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