anonymous
  • anonymous
HELP!! A projectile is launched straight up at 62.5 m/s from a height of 73.5 m, at the edge of a sheer cliff. The projectile falls, just missing the cliff and hitting the ground below. (a) Find the maximum height of the projectile above the point of firing. (m) (b) Find the time it takes to hit the ground at the base of the cliff. (s) (c) Find its velocity at impact. (m/s)
Physics
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anonymous
  • anonymous
HELP!! A projectile is launched straight up at 62.5 m/s from a height of 73.5 m, at the edge of a sheer cliff. The projectile falls, just missing the cliff and hitting the ground below. (a) Find the maximum height of the projectile above the point of firing. (m) (b) Find the time it takes to hit the ground at the base of the cliff. (s) (c) Find its velocity at impact. (m/s)
Physics
chestercat
  • chestercat
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anonymous
  • anonymous
a)maximum height , Hmax = v^2/(2 * g)
anonymous
  • anonymous
a) maximum height = 62.5^2/(2 * 9.8) maximum height =199.3 m
anonymous
  • anonymous
b) let the time taken to fall is t Using second equation of motion y = ut + 0.5 at^2 -73.5 = 62.5 * t - 0.5 * 9.8 t^2 solving for t t = 13.8 s the time taken to fall is 13.8 s

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anonymous
  • anonymous
part c) let the velocity of impact is v m/s using third equation of motion v^2 - u^2 = 2 * a * d
anonymous
  • anonymous
v^2 - 62.5^2 = 2 * 9.8 * 73.5 solving for v v = 73.12 m/s the velocity of impact is 73.12 m/s

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