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amy0799
 one year ago
Find d2^y/dx^2 in terms of x and y.
amy0799
 one year ago
Find d2^y/dx^2 in terms of x and y.

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madhu.mukherjee.946
 one year ago
Best ResponseYou've already chosen the best response.02xy^2+x^2(2y)dy/dx8=0

amy0799
 one year ago
Best ResponseYou've already chosen the best response.0I already have the first derivative figured out, I don't know how to find the second though

madhu.mukherjee.946
 one year ago
Best ResponseYou've already chosen the best response.0just change the sides take evrything to right side except x^2(2y)dy/dx

amy0799
 one year ago
Best ResponseYou've already chosen the best response.0do I just plug in x^2y^2−8x into the derivative of d2^y/dx^2?

madhu.mukherjee.946
 one year ago
Best ResponseYou've already chosen the best response.0nope u do like this dw:1442671687613:dw

madhu.mukherjee.946
 one year ago
Best ResponseYou've already chosen the best response.0do you understand

amy0799
 one year ago
Best ResponseYou've already chosen the best response.0umm not really, is that for dy/dx?

amy0799
 one year ago
Best ResponseYou've already chosen the best response.0how? I cant really read what you drew

madhu.mukherjee.946
 one year ago
Best ResponseYou've already chosen the best response.0okay both the drawings

amy0799
 one year ago
Best ResponseYou've already chosen the best response.0can you type out ur equations please?

madhu.mukherjee.946
 one year ago
Best ResponseYou've already chosen the best response.0dy/dx=8/x^2y2xy^2/x^22y dy/dx=4/x^2yy/x

madhu.mukherjee.946
 one year ago
Best ResponseYou've already chosen the best response.0now do double derivative

amy0799
 one year ago
Best ResponseYou've already chosen the best response.0I got the first derivative to be \[\frac{ xy ^{2}4 }{ x^{2}y }\]

madhu.mukherjee.946
 one year ago
Best ResponseYou've already chosen the best response.0nope i told the first one

madhu.mukherjee.946
 one year ago
Best ResponseYou've already chosen the best response.0this is not normal derivative this is implicit differentiation

amy0799
 one year ago
Best ResponseYou've already chosen the best response.0I know but when I did the implicit differentiation for x^2y^2−8x=2 I got that equation and it's different than yours

madhu.mukherjee.946
 one year ago
Best ResponseYou've already chosen the best response.0yeah i'm sorry dude you are correct

madhu.mukherjee.946
 one year ago
Best ResponseYou've already chosen the best response.0i'm so sorry actually i've simplified it a bit

amy0799
 one year ago
Best ResponseYou've already chosen the best response.0how did you simplify it?

madhu.mukherjee.946
 one year ago
Best ResponseYou've already chosen the best response.0forget that what you did is absolutely correct

madhu.mukherjee.946
 one year ago
Best ResponseYou've already chosen the best response.0but u made a mistake with the signs it will be 4xy^2/x^2y

amy0799
 one year ago
Best ResponseYou've already chosen the best response.0oh ok. so I just find the derivative of that?

amy0799
 one year ago
Best ResponseYou've already chosen the best response.0ok. ill show u what I get in a minute

madhu.mukherjee.946
 one year ago
Best ResponseYou've already chosen the best response.0no problem

amy0799
 one year ago
Best ResponseYou've already chosen the best response.0I got \[\frac{ x ^{2}y(2xyy'y ^{2})(4xy ^{2})(x ^{2}y'+2xy) }{ y ^{2}x ^{4} }\] correct so far?

amy0799
 one year ago
Best ResponseYou've already chosen the best response.0is what I had right so far?

madhu.mukherjee.946
 one year ago
Best ResponseYou've already chosen the best response.0anything more

amy0799
 one year ago
Best ResponseYou've already chosen the best response.0well I still haven't found the 2nd derivative.

amy0799
 one year ago
Best ResponseYou've already chosen the best response.0@IrishBoy123 can u help?

madhu.mukherjee.946
 one year ago
Best ResponseYou've already chosen the best response.0dude this is the second derivative

amy0799
 one year ago
Best ResponseYou've already chosen the best response.0ik but there should be more to it

madhu.mukherjee.946
 one year ago
Best ResponseYou've already chosen the best response.0see if you are able to simplify it more but this is f9

madhu.mukherjee.946
 one year ago
Best ResponseYou've already chosen the best response.0yeah i mean fine

madhu.mukherjee.946
 one year ago
Best ResponseYou've already chosen the best response.0this is correct

amy0799
 one year ago
Best ResponseYou've already chosen the best response.0don't I need to plug in 4xy^2/x^2y into dy/dx?

amy0799
 one year ago
Best ResponseYou've already chosen the best response.0I got \[\frac{ 2x^2 y^58xy^316}{ y}\] but that's the wrong answer when I summited it

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.0your first deriv looks wrong way round for starters

amy0799
 one year ago
Best ResponseYou've already chosen the best response.0what is it suppose to be?

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.0should be \[\color{red}  \frac{ xy ^{2}4 }{ x^{2}y }\]

madhu.mukherjee.946
 one year ago
Best ResponseYou've already chosen the best response.0nope the first derivative done by amy is f9

madhu.mukherjee.946
 one year ago
Best ResponseYou've already chosen the best response.0i've checked that in wolfram alpha

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.0you can then do it implicitly starting \[y' .x^2 .y = 4  xy^2 \] and applying the triple product, see here dw:1442677649641:dw but, whatever way you do it, it's horrible.

amy0799
 one year ago
Best ResponseYou've already chosen the best response.0@IrishBoy123 how would I find the answer?

madhu.mukherjee.946
 one year ago
Best ResponseYou've already chosen the best response.0your second derivative is wrong

madhu.mukherjee.946
 one year ago
Best ResponseYou've already chosen the best response.0y^2(y3xy'(x))/x^2

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.0first deriv \[x ^{2}y ^{2}8x=2\] \[2x y ^{2} + x^22yy'8 = 0\] \[y' = \frac{82xy^2}{2x^2y} = ....\]ie wrong for second deriv you **might** go: \[ (x^2)(y)(y')=4 x y ^{2} \] \[ (x^2)'(y)(y') +(x^2)(y)'(y')+(x^2)(y)(y')' = y^22xyy'\] at some point you plug in for y'

amy0799
 one year ago
Best ResponseYou've already chosen the best response.0isn't that gonna be a big number when I plug in y'?

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.0it's going to be horrible whatever way you do it. i have a feeling this could be a more organised way to do it, but if you are most of the way through, carry on as before however, do check that first derivative again or you will never get there
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