Loser66
  • Loser66
Prove SSS theorem. Please, help.
Mathematics
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SOLVED
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schrodinger
  • schrodinger
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Loser66
  • Loser66
@zzr0ck3r
Loser66
  • Loser66
@dan815
jackthegreatest
  • jackthegreatest
I can help but wats the problem?

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More answers

Loser66
  • Loser66
Prove SSS theorem, that is the problem.
jackthegreatest
  • jackthegreatest
Oh I thought u had to prove two triangles similar using sss
Loser66
  • Loser66
\(\triangle ABC \) and \(\triangle A'B'C'\) such that AB = A'B', AC = A'C', BC = B'C'. Prove that \(\triangle ABC \cong \triangle A'B'C'\)
jackthegreatest
  • jackthegreatest
I can't help on proving theorem itself sorry
jackthegreatest
  • jackthegreatest
Hmmm
Loser66
  • Loser66
It's ok, friend. Thanks for being here.
jackthegreatest
  • jackthegreatest
Sorry can't help
anonymous
  • anonymous
SSS is a postulate
zzr0ck3r
  • zzr0ck3r
right, I don't think you prove this one. It would be like proving The Axiom of Choice without one of its equivalents.
Loser66
  • Loser66
Thanks for replying, but yes, we are and I have it done.
Loser66
  • Loser66
@oldrin.bataku @zzr0ck3r , this course is modern geometry. We learn how to prove a theorem (and SSS is a theorem, not postulate). The course is to train high school teacher how to teach geometry.
zzr0ck3r
  • zzr0ck3r
ahh, I never took geometry but when I googled it, it seemed like it was not something you prove.
anonymous
  • anonymous
SSS is a postulate in the original formulation of Euclidean geometry: https://en.wikipedia.org/wiki/SSS_postulate depending on what alternative axiomatization you use for your modern geometry course, sure, you can prove it from that alternative foundation, but without stating that before it is only natural to assume we're talking about classical Euclidean geometry. it is impossible to even answer your question without your axiomatization anyways so this question as it stands is ill-posed and impossible to answer

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