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AmTran_Bus
 one year ago
Show c1 sin omega t + c2 cos omega t is equal to A sin (omega t + phi)
AmTran_Bus
 one year ago
Show c1 sin omega t + c2 cos omega t is equal to A sin (omega t + phi)

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AmTran_Bus
 one year ago
Best ResponseYou've already chosen the best response.0dw:1442673851220:dw The issue is that I do not understand what omega or phi is.

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.1Did you try to compare both equations?

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.1\[A\sin(\omega t + \phi) \]\[= c_1 \sin (\omega t) + c_2 \cos(\omega t)\]\[= \color{#c00}{A\cos (\phi)} \sin (\omega t) + \color{#C00}{A \sin (\phi)} \cos(\omega t) \]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Basically \[\omega,\phi,A\] These 3 quantities are constant while t is variable, so as @ParthKohli has highlighted, the quantity Acos(phi) and Asin(phi) may be clubbed together as a single constant like \[C_{1}=A\cos(\phi) \space \space \space ,\space \space \space C_{2}=A\sin(\phi)\]
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