anonymous
  • anonymous
Explain the distance formula. Then use it to calculate the distance between A(1, 1) and B(7,­7).
Mathematics
katieb
  • katieb
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Mehek14
  • Mehek14
\(\bf{D = \sqrt{(y_2-y_1)^2+(x_2-x_1)^2}}\)
Mehek14
  • Mehek14
that is the formula
Mehek14
  • Mehek14
|dw:1442680083148:dw|

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rishavraj
  • rishavraj
http://www.purplemath.com/modules/distform.htm
Mehek14
  • Mehek14
so plug in the numbers into the formula
anonymous
  • anonymous
|dw:1442680584634:dw|
Mehek14
  • Mehek14
\(\bf{\sqrt{(7-1)^2+(7-1)^2}}\)
Mehek14
  • Mehek14
so subtract 7-1 = 7-1 =
anonymous
  • anonymous
That would be 6 and 6.
Mehek14
  • Mehek14
\(6^2\\6^2\)
anonymous
  • anonymous
So what do you do with the 6^2 ?
Mehek14
  • Mehek14
find \(6^2\\6^2\)
anonymous
  • anonymous
6^2 = 36
Mehek14
  • Mehek14
36 + 36 = ?
anonymous
  • anonymous
72
Mehek14
  • Mehek14
\(\sqrt{72}\)
anonymous
  • anonymous
Why would it be squared 72?
Mehek14
  • Mehek14
\(\bf{D = \sqrt{(y_2-y_1)^2+(x_2-x_1)^2}}\)
Mehek14
  • Mehek14
this is what we did \(\bf{D = \sqrt{(y_2-y_1)^2+(x_2-x_1)^2}}\) \(\bf{D = \sqrt{(7-1)^2+(7-1)^2}}\) \(\bf{D = \sqrt{(6)^2+(6)^2}}\) \(\bf{D = \sqrt{36+36}}\) \(\bf{D = \sqrt{72}}\)
anonymous
  • anonymous
|dw:1442693028016:dw|

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