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calculusxy
 one year ago
Help with exponents!
(x^4)^{3} x 2x^4
calculusxy
 one year ago
Help with exponents! (x^4)^{3} x 2x^4

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rishavraj
 one year ago
Best ResponseYou've already chosen the best response.0\[(a^x)^y = a^{xy}~~~~~~~~~a^x \times a^y = a^{x + y}\]

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.0Sorry i meant 1/x^12 x 2x^4

rishavraj
 one year ago
Best ResponseYou've already chosen the best response.0okay see(x^4)^{3} = x^{12}

rishavraj
 one year ago
Best ResponseYou've already chosen the best response.0now u got \[x^{12} \times 2 \times x^4\] so use a^x + a^y = a^{x + y}

rishavraj
 one year ago
Best ResponseYou've already chosen the best response.0question is \[(x^4)^{3} \times 2x^4\]

rishavraj
 one year ago
Best ResponseYou've already chosen the best response.0so u got 2*x*{8} u can write it as 2/(x^{}8) or just 2x^{8}

rishavraj
 one year ago
Best ResponseYou've already chosen the best response.0u know \[\frac{ 1 }{ a^x } = a^{x}\]

rishavraj
 one year ago
Best ResponseYou've already chosen the best response.0so here u having \[2x^{8}\] just leave it tht way :)

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.0But why do i need to combine them? R they like terms and, if so, why?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0these are the exponents rules when we multiply same bases we should `add` exponents \[\huge\rm x^m \times x^n=x^{m+n}\] and when we divide same base , `subtract` their exponents \[\huge\rm \frac{ x^m }{ x^n }=x^{mn}\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0\(\color{blue}{\text{Originally Posted by}}\) @rishavraj u know \[\frac{ 1 }{ a^x } = a^{x}\] \(\color{blue}{\text{End of Quote}}\) if there is negative exponents we should flip the fraction when we flip the fraction sign of the exponent would change

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0that's for negative exponent rule he gave u^^^^

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0\(\color{blue}{\text{Originally Posted by}}\) @calculusxy But why do i need to combine them? R they like terms and, if so, why? \(\color{blue}{\text{End of Quote}}\) like base

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.0So the 2 doesn't matter? @Nnesha

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0multiply the coefficient x is same as 1x \[\huge\rm1 x^{12} \times 2x^4=(1 \times 2)x^{12+4}\]

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.0Okay so 2x^4 has two terms right? Since 2 is being multiplied with x^4, the two is one term and x^4 is another?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0sorry for late reply not getting notification so plz tag the username :=) no 2x^4 is only one term not two terms: number or variable that are separated by `+` or `` sign

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0so 2x^4 is only one term when we multiply we should focus on the base when you `ADD or subtract ` like terms u just have to deal with the coefficients like \[2x+3x=(2+3)x\] but when we multiply same bases we should `add` their exponents and multiply the coefficien\[\huge\rm \color{Red}{1}x^m · \color{blue}{1}x^n=(\color{red}{1} ·\color{blue}{1})x^{m+n}\]ts as well
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