calculusxy
  • calculusxy
Help with exponents! (x^4)^{-3} x 2x^4
Mathematics
  • Stacey Warren - Expert brainly.com
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jamiebookeater
  • jamiebookeater
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rishavraj
  • rishavraj
\[(a^x)^y = a^{xy}~~~~~~~~~a^x \times a^y = a^{x + y}\]
calculusxy
  • calculusxy
Sorry i meant 1/x^12 x 2x^4
rishavraj
  • rishavraj
hmmm v???

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calculusxy
  • calculusxy
No i wrote x
rishavraj
  • rishavraj
okay see(x^4)^{-3} = x^{-12}
calculusxy
  • calculusxy
Yes...
rishavraj
  • rishavraj
now u got \[x^{-12} \times 2 \times x^4\] so use a^x + a^y = a^{x + y}
calculusxy
  • calculusxy
x^{-8}
rishavraj
  • rishavraj
question is \[(x^4)^{-3} \times 2x^4\]
calculusxy
  • calculusxy
Yes
rishavraj
  • rishavraj
so u got 2*x*{-8} u can write it as 2/(x^{}8) or just 2x^{-8}
calculusxy
  • calculusxy
I dont understand
rishavraj
  • rishavraj
u know \[\frac{ 1 }{ a^x } = a^{-x}\]
rishavraj
  • rishavraj
so here u having \[2x^{-8}\] just leave it tht way :)
calculusxy
  • calculusxy
But why do i need to combine them? R they like terms and, if so, why?
Nnesha
  • Nnesha
these are the exponents rules when we multiply same bases we should `add` exponents \[\huge\rm x^m \times x^n=x^{m+n}\] and when we divide same base , `subtract` their exponents \[\huge\rm \frac{ x^m }{ x^n }=x^{m-n}\]
Nnesha
  • Nnesha
\(\color{blue}{\text{Originally Posted by}}\) @rishavraj u know \[\frac{ 1 }{ a^x } = a^{-x}\] \(\color{blue}{\text{End of Quote}}\) if there is negative exponents we should flip the fraction when we flip the fraction sign of the exponent would change
Nnesha
  • Nnesha
that's for negative exponent rule he gave u^^^^
Nnesha
  • Nnesha
\(\color{blue}{\text{Originally Posted by}}\) @calculusxy But why do i need to combine them? R they like terms and, if so, why? \(\color{blue}{\text{End of Quote}}\) like base
calculusxy
  • calculusxy
So the 2 doesn't matter? @Nnesha
Nnesha
  • Nnesha
multiply the coefficient x is same as 1x \[\huge\rm1 x^{-12} \times 2x^4=(1 \times 2)x^{-12+4}\]
calculusxy
  • calculusxy
Okay so 2x^4 has two terms right? Since 2 is being multiplied with x^4, the two is one term and x^4 is another?
Nnesha
  • Nnesha
sorry for late reply not getting notification so plz tag the username :=) no 2x^4 is only one term not two terms: number or variable that are separated by `+` or `-` sign
Nnesha
  • Nnesha
so 2x^4 is only one term when we multiply we should focus on the base when you `ADD or subtract ` like terms u just have to deal with the coefficients like \[2x+3x=(2+3)x\] but when we multiply same bases we should `add` their exponents and multiply the coefficien\[\huge\rm \color{Red}{1}x^m · \color{blue}{1}x^n=(\color{red}{1} ·\color{blue}{1})x^{m+n}\]ts as well
Nnesha
  • Nnesha
coefficient *

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