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First, subtract 1 from both sides

ok :)

what should I do next

Use the draw feature to Post your work

|dw:1442685887228:dw|

sorry it's really messy

That's perfect. Next rewrite 1 As A fraction So that both fractions have the same denominator

|dw:1442686057579:dw|

|dw:1442686299242:dw|

Hang on a minute.

alrighty :)

the denominator doesn't cancel out?

i did and i got 1 :/

Let me ask you this: What is 5/6 minus 2/6

|dw:1442686808756:dw|

3/6

i seeee

How come you didn't do 6-6 to get zero?

ok so now it's|dw:1442686906249:dw|

that's how i learned it you don't subtract when they're the same :) ok i see what you're saying

perfect. Now factor the denominator.

|dw:1442686993828:dw|

Very good. Now we should make A number line and plot our critical points. Any ideas on that?

what're critical points?

3 and -2?

correct, now draw a number line that induces those points.

|dw:1442687325243:dw|

Or rather, that excludes those points. Hence open circle

is that correct

I recommend writing the number line this way for clarity And Simplicity

okay

alright

Next we Will test convenient Values between the critical points by inserting those convenient points from each interval into the factored expression.

One easy convenient Value We can test is x=0

If it passes the test, then the interval x=0 comes from is at least one Of the solutions

it does not pass it

Okay, if not then, We can eliminate that interval ( -2 , 3) as a possible solution

try testing one value from each of the other two Intervals.

-1 does not work either

1 works

-1 is from the interval ( -2 , 3)

We already eliminated that Interval

wait but 1 worked

Okay sorry, We need to line modify our number line because 1 is also a critical point.

oh yeahhhhh

okay i see

the circle is shaded in for 1 right?

ok nice nice

So We have 4 intervals now that We need to test. Pick values from each.

2 is true

Let me know what works and What doesn't

-3 also works

I agree the 2 And-3 Works. Anything else?

-4 also

same interval *

4 does not work

I've tried from all intervals now

-3 works

-1 and 0 don't

2 works

and 4 does not

So what is the solution for the original inequality?

in interval notation it'd be

|dw:1442689021631:dw|

Congratulations, you've earned a medal for your hard work.

thank you!! can you tell me the difference between set notation and interval notation?

If you have any questions about it feel free to ask

i understand the interval notation but the set notation throws me off, how could i write it

what're descriptive components

okay so in this case i want to represent the number line right

Yes, give it a Shot

|dw:1442690853126:dw| ://

Well, not exactly. First you hare to rewrite each Interval notation as an inequality.

how could i do that

For example ( a,b) means the same as a

|dw:1442691229604:dw|

Okay, now Write the set notation and include all the appropriate Components,

Oh, don't forget to use the correct inequality symbol for Inclusion

|dw:1442691352299:dw|

That's almost perfect but we don't know what Kind of set x IS.

mm what do you mean?

X belongs to what kind of Set? Integers?, natural numbers? Real Numbers?

real numbers

Correct

Add that to your set builder notation.

Okay

Create a new question though.

okay