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okay so I got to the point where I dont know what to do next

I got the system to row echelon form

lt me draw what i got out

|dw:1442684208867:dw|

Do I need to put this into reduce echelon form?

Actually yea I think that would help

let me do that on paper, first brb

oh wait made a mistake in the drawing, the "3a+10" has a denominator of "2a-4"

|dw:1442685001288:dw|

find the determinant and set it to zero and that might save a lot of typing

ie set to zero and solve for a

I assume you mean the determinant of the coefficient matrix.

if a = 2 you have a contradiction, can you see why?

It will be no solution if u get set a = 2

correct

So would it be right to say that this system does not have infinite solutions?

anyone there?

it will never have infinite solutions

what I'm confused about is that if a does not equal to 2, will it have infinite solutions

oh ok, can you tell me why though?

oooh I see, lol thanks, I blanked out for a second there. Thank you so much!

Your welcome.

|dw:1442690538127:dw|

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