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calculusxy
 one year ago
Help with exponents!
Question posted below... MEDAL!
calculusxy
 one year ago
Help with exponents! Question posted below... MEDAL!

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calculusxy
 one year ago
Best ResponseYou've already chosen the best response.1\[\huge (x^4)^{3} \times 2x^4\]

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2first term \(\huge (a^b)^c = a^{bc}\)

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2you subtracted the exponents, the rule tell us to multiply them :3

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.1I am running our of my mind :\

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2\(4 \times (3) =  (4\times 3) = .. \)

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.1\[\huge x^{4 \times (3)} = x^{12}\]

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2now \(\huge a^b \times a ^c = a^{b+c}\)

hartnn
 one year ago
Best ResponseYou've already chosen the best response.22 \((x^{12} \times x^4) = .. ?\)

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.1So here's the thing, I don't why we have to combine them... Is it because 2x^4 has two terms: 2 and x^4?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0theres a common base, \(x\)

hartnn
 one year ago
Best ResponseYou've already chosen the best response.22 is a constant, lets throw that out of the process of multiplying 'x's

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.1So just to clarify, if we have like 45x^5 then i will just have to take out the 45 and work with the x being the common base with another power right?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2....with another term of x. yes.

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.1\[\large 2(x^{8}) = 2x^{8}\]

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2\(2 x^3 \times 45 x^5 = 2\times 45 x^{3+5}\)

hartnn
 one year ago
Best ResponseYou've already chosen the best response.22/x^8 also "looks" nice

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.1My answer is \[\huge \frac{ 2 }{ x^8 }\]

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.1The reason for why I have to put the x^8 to the denominator is because of the exponent of 8 right? The negative exponent tells the base to get to its reciprocal and then the exponent becomes positive?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2correcto! \(\Large a^{b} = \dfrac{1}{a^b}\)
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