## help_people one year ago For f(x) = x2 and g(x) = (x − 4)2, in which direction and by how many units should f(x) be shifted to obtain g(x)? Left 4 units Up 4 units Right 4 units Down 4 units

1. anonymous

for a function $f(x)$ We have the following ways of how the graph moves $f(x+a)$ Moves the graph LEFT by a units $f(x-a)$ moves the graph RIGHT by a units $f(x)+a$ moves the graph UP by a units $f(x)-a$ moves the graph DOWN by a units, so what do you think?

2. anonymous

If you think about it as a parabolic function in vertex form, $$y=a(x-h)^2+k$$ You can determine that your vertex is at $$(4~,~0)$$ whereas the vertex of the parent function is $$(0~,~0)$$. Comparing the two vertexes, you can tell which way your graph has moved, what is the change from $$4\rightarrow 0=~?$$

3. help_people

so a ? @Jhannybean and @Nishant_Garg srry my mom called me :/

4. help_people

srrry i was inactive :)

5. anonymous

a would be $$g(x) =(x+4)^2$$

6. help_people

? thats now what nishant said

7. anonymous

No, @Nishant_Garg gave you the different variations of HOW the graph would move in certain situations.

8. anonymous

You can also compare the vertices.. and notice how theyve changed.

9. anonymous

i mean vertexes*

10. anonymous

|dw:1442689805859:dw|

11. anonymous

Which way does it LOOK like it's moving?...

12. help_people

to the right

13. help_people

4 times

14. help_people

@Jhannybean so c?

15. anonymous

Yep

16. help_people

ok great thanks :)

17. help_people

can i tag you if i have any more questions?

18. mathmate

What @Nishant_Garg said is still true, we only have to read with care. This is what he wrote, with line spacings rearranged. for a function f(x) We have the following ways of how the graph moves f(x+a) Moves the graph LEFT by a units f(x−a) moves the graph RIGHT by a units f(x)+a moves the graph UP by a units f(x)−a moves the graph DOWN by a units, so what do you think?