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for a function \[f(x)\] We have the following ways of how the graph moves \[f(x+a)\] Moves the graph LEFT by a units \[f(x-a)\] moves the graph RIGHT by a units \[f(x)+a\] moves the graph UP by a units \[f(x)-a\] moves the graph DOWN by a units, so what do you think?
If you think about it as a parabolic function in vertex form, \(y=a(x-h)^2+k\) You can determine that your vertex is at \((4~,~0)\) whereas the vertex of the parent function is \((0~,~0)\). Comparing the two vertexes, you can tell which way your graph has moved, what is the change from \(4\rightarrow 0=~?\)
so a ? @Jhannybean and @Nishant_Garg srry my mom called me :/
srrry i was inactive :)
a would be \(g(x) =(x+4)^2\)
? thats now what nishant said
No, @Nishant_Garg gave you the different variations of HOW the graph would move in certain situations.
You can also compare the vertices.. and notice how theyve changed.
i mean vertexes*
Which way does it LOOK like it's moving?...
to the right
@Jhannybean so c?
ok great thanks :)
can i tag you if i have any more questions?
What @Nishant_Garg said is still true, we only have to read with care. This is what he wrote, with line spacings rearranged. for a function f(x) We have the following ways of how the graph moves f(x+a) Moves the graph LEFT by a units f(x−a) moves the graph RIGHT by a units f(x)+a moves the graph UP by a units f(x)−a moves the graph DOWN by a units, so what do you think?