## calculusxy one year ago Help with exponents! @hartnn

1. calculusxy

$\huge (2v)^2 \times 2v^2$

2. calculusxy

$\large (2v)^2 = 2^2 \times v^2 = 4v^2$ $\large 4v^2 \times 2v^2 = 8v^2$ or does it equal to$\large 8v^4$

3. Nnesha

$\huge\rm (ab)^m =a^m b^m$ apply this exponent first both number in the parentheses are raising to the m power

4. Nnesha

looks good!

5. calculusxy

So which one does it equal to?

6. calculusxy

$\large 8v^2$ or $\large 8v^4$

7. Nnesha

ohh i see well when we multiply same bases we should ADD their exponents

8. calculusxy

oh okay so it is $8v^4$ right?

9. Nnesha

remember it's not combine like terms $2x+3x=(2+3)x$ when we add/subtract like terms variable stay the same but when we multiply them we should add their exponents

10. Nnesha

yes right

11. calculusxy

I have another question @Nnesha

12. Nnesha

okay :=)

13. Nnesha

when you ADD or subtract  like terms u just have to deal with the coefficients like $2x+3x=(2+3)x$ but when we multiply same bases we should add their exponents and multiply the coefficient$\huge\rm \color{Red}{1}x^m · \color{blue}{1}x^n=(\color{red}{1} ·\color{blue}{1})x^{m+n}$

14. calculusxy

$\huge \frac{ 2x^2y^4 \times 4x^2y^4 \times 3x }{ 3x^{-3}y^2 }$

15. Nnesha

ayoooXD

16. anonymous

I guess you forget what he/she did there lol

17. Nnesha

multiply the coefficients and add the exponent of the same base

18. Nnesha

$\huge \frac{ 2x^2y^4 \times 4x^2y^4 \times 3x }{ 3x^{-3}y^2 }$ can be written as $\frac{ (2·4·3)(x^2·x^2·x)(y^4·y^4) }{3x^{-3}y^2 }$

19. Nnesha

and x is same as x^1

20. calculusxy

$\large \frac{ 16x^5y^8 }{3x^{-3}y^2 } = \frac{ 16x^8y^6 }{ 3 }$

21. Nnesha

(2 times 3 times 4) isn't equal to 16 :=) x^8 and y^6 is correct

22. calculusxy

sorry 24

23. Nnesha

yes 24/3 simplify done!

24. calculusxy

8

25. Nnesha

that's it great job!

26. calculusxy

Thank you! If i need more help can i mention you...?

27. Nnesha

sure!