calculusxy
  • calculusxy
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Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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calculusxy
  • calculusxy
\[\huge \frac{ x }{ (2x^0)^2 }\]
calculusxy
  • calculusxy
\[\large \frac{ x }{ 4 }\]
calculusxy
  • calculusxy
@Nnesha

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More answers

Nnesha
  • Nnesha
what happened to x^0 :o ???
calculusxy
  • calculusxy
\[\large (2x^0)^2 = 2^2 \times (x^0)^2 = 4 \times x^0 = 4 \times 1 = 4\] would the x^0 be considered as 1 ?
Nnesha
  • Nnesha
PERFECT!yes (anything)^0 = !
Nnesha
  • Nnesha
1**
calculusxy
  • calculusxy
So my answer is correct?
Nnesha
  • Nnesha
yes!
calculusxy
  • calculusxy
Thank you!
hartnn
  • hartnn
(anything except 0)^0 = 1
Nnesha
  • Nnesha
np :=)
Nnesha
  • Nnesha
ye (hartnn)^0= 1
hartnn
  • hartnn
yay! i am non-0 :P :D
Nnesha
  • Nnesha
ohh wait i just noticed double nn's at the end of ur username!! :o
hartnn
  • hartnn
and at the beginning of yours :)
Nnesha
  • Nnesha
yeah hahah
hartnn
  • hartnn
hartnnesha
hartnn
  • hartnn
LOL!
Nnesha
  • Nnesha
heheh ^.*

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