calculusxy
  • calculusxy
Exponents ...
Mathematics
jamiebookeater
  • jamiebookeater
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calculusxy
  • calculusxy
calculusxy
  • calculusxy
\[\huge \frac{ (2m^2)^{-1} }{ m^2 }\]
calculusxy
  • calculusxy
\[\large \frac{ 1 }{ 2m^1 }\]

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hartnn
  • hartnn
\(\dfrac{m^{-2}}{m^2 } = \dfrac{1}{m^2 \times m^2 }\)
anonymous
  • anonymous
\[x ^{-1}=\frac{ 1 }{ x^1 }\]
hartnn
  • hartnn
how did you get m^1 ?
anonymous
  • anonymous
Hartnn can you help me with my problem after her ?
hartnn
  • hartnn
I'll try rosie :)
calculusxy
  • calculusxy
\[\large (2m^2)^{-1} = 2^{-1}m^{2-(-1)} = 2^{-1}m^3\]
hartnn
  • hartnn
\(\Huge (a^b)^c = a^{bc}\)
hartnn
  • hartnn
\(\Large (m^2)^{-1} = m^{-2}\)
calculusxy
  • calculusxy
oh yes sorry my mistake once again...
hartnn
  • hartnn
np :) m^-2 = 1/m^2
calculusxy
  • calculusxy
would 2^{-1} be 1/2^1
hartnn
  • hartnn
yesss
calculusxy
  • calculusxy
and then m^{-2 - 2} = m^{-4} = 1/m^4
calculusxy
  • calculusxy
would the answer be like \[\large \frac{ 1 }{ 2^1m^4 }\]
hartnn
  • hartnn
write 2^2 as 2 only :) and yes
hartnn
  • hartnn
i mean 2^1 =2
calculusxy
  • calculusxy
ok thank you

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