At the National Physical Laboratory in England, a measurement of the free-fall acceleration g was made by throwing a glass ball straight up in an evacuated tube (the air was pumped out) and letting the ball return. Let ΔTL in the figure below be the time interval between the two passages of the ball across a certain lower level, ΔTU the time interval between the two passages across an upper level, and H the distance between the two levels. What is ||g|| in terms of the measurements taken?

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

At the National Physical Laboratory in England, a measurement of the free-fall acceleration g was made by throwing a glass ball straight up in an evacuated tube (the air was pumped out) and letting the ball return. Let ΔTL in the figure below be the time interval between the two passages of the ball across a certain lower level, ΔTU the time interval between the two passages across an upper level, and H the distance between the two levels. What is ||g|| in terms of the measurements taken?

Physics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

And the figure?
1 Attachment
|dw:1442819505362:dw|

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

|dw:1442825943411:dw| setting the coordinates as shown to simplify algebra and using equation of motion \(x = ut + \frac{1}{2}at^2 = t(u+\frac{1}{2}at)\), we can say \(\large 0 = t(u+\frac{1}{2}at) \implies t_{o1} = 0, t_{o2} =\Delta T_L = -\frac{2u}{a}\) we can also say \(\large H = ut + \frac{1}{2}at^2 \implies at^2 +2ut - 2H = 0\) and from the quadratic formula we now know that \(\large \Delta T_U = 2 \times \frac{\sqrt{(2u)^2 - (4)(a)(-2H)}}{2a} \) but that's an ugly way to do it, especially given how neat it suggests the solution is.
|dw:1442827632092:dw| exploiting this symmetry might provide a more fun solution

Not the answer you are looking for?

Search for more explanations.

Ask your own question