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anonymous
 one year ago
Express the complex number in trigonometric form.
3 + 3 square root of three i
anonymous
 one year ago
Express the complex number in trigonometric form. 3 + 3 square root of three i

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jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2I'm assuming the expression given is \(\Large 3+3\sqrt{3}*i\) If so, then it's the same as last time but now \[\Large a = 3\] \[\Large b = 3\sqrt{3}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeah, that is the correct expression

Plasmataco
 one year ago
Best ResponseYou've already chosen the best response.0quick question... what is the square root of i?

Plasmataco
 one year ago
Best ResponseYou've already chosen the best response.0I know... im a little slow with the noggin but still...

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2the i isn't part of the square root

Plasmataco
 one year ago
Best ResponseYou've already chosen the best response.0i know, just curios.

Plasmataco
 one year ago
Best ResponseYou've already chosen the best response.0i thought that was the square... exponent 2.

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2\[\Large i = \sqrt{1}\] \[\Large i^2 = (\sqrt{1})^2\] \[\Large i^2 = 1\]

Plasmataco
 one year ago
Best ResponseYou've already chosen the best response.0am i just the stupid idiot here or u genuinely dont know or connection problemos?

Plasmataco
 one year ago
Best ResponseYou've already chosen the best response.0square root. sry like radical.

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2sorry @Plasmataco I'm not following

Plasmataco
 one year ago
Best ResponseYou've already chosen the best response.0i know but like 1 under a radical of 4

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2were you able to find r and theta, @lxoser ?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2oh you mean \[\Large \sqrt{i} = \sqrt[4]{1}\] @Plasmataco ??

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0im gonna need help finding r and theta @jim_thompson5910

Plasmataco
 one year ago
Best ResponseYou've already chosen the best response.0sry for interrupting...

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2\[\Large r = \sqrt{a^2 + b^2}\] \[\Large r = \sqrt{3^2 + (3\sqrt{3})^2}\] ... ... ... \[\Large r = ??\]

Plasmataco
 one year ago
Best ResponseYou've already chosen the best response.0it should be somthing a lot lower

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2Hint: \[\Large (3\sqrt{3})^2=(3\sqrt{3})*(3\sqrt{3})\] \[\Large (3\sqrt{3})^2=(3*3)*(\sqrt{3}*\sqrt{3})\] \[\Large (3\sqrt{3})^2=(3*3)*\sqrt{3*3}\] \[\Large (3\sqrt{3})^2=9\sqrt{9}\] \[\Large (3\sqrt{3})^2=9*3\] \[\Large (3\sqrt{3})^2=27\]

Plasmataco
 one year ago
Best ResponseYou've already chosen the best response.0horay! now my question.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0for theta, i got 60?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0is the result suppose to be in radians or degrees?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2it depends on what the instructions say

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2does it say which mode they want?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no, but these are the answer choices

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2ok so they want radian form

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so would theta be  pi/3

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2yes, now because our point is in Q2 (see graph) we add pi radians to our angle to land in the right quadrant dw:1442707471746:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2 pi/3 is in Q4 dw:1442707591362:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2so we have to add 180 degrees or pi radians to get it into the right quadrant dw:1442707637525:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so would the answer be 6(cos 2pi/3 + i sin 2pi/3) ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thank you so much!! :")
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