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can you tell me what this length is? |dw:1442710140915:dw|
no the 7 is the vertical dimension I'm asking for the total horizontal dimension
idk how you're getting that
do you see the stuff I circled?
add them up to get ???
2x or x^2
x + 8 + x = ???
think of it like this `apple + apple = 2 apples` so `x + x = 2x` right?
so if x+x = 2x, then x+x+8 turns into what?
so hopefully you see how that total length marked in the drawing is 2x+8 feet?
i finally do :D
what is this marked length here? |dw:1442711082155:dw|
now if the length was 2x+8 and the width was 2x+7, then what is the area of the rectangle?
you have to multiply (2x+8) with (2x+7) FOIL it out
could you show me ?
have you learned the box method? that's actually better than FOIL
good, you used the box method to get that? or some other method?
so the entire area of the rectangle (larger rectangle) is `4x^2+30x+56` they tell us that "The painting and frame must have an area of 58 square feet." so equate the two areas 4x^2+30x+56 = 58
now get everything to one side
subtract 58 from both sides
0 be left on the other side (since 58-58 = 0) so we have this answer `4x^2 + 30x - 2 = 0`
tahnks alot for everything :)