help_people
  • help_people
Tabitha wants to hang a painting in a gallery. The painting and frame must have an area of 58 square feet. The painting is 7 feet wide by 8 feet long. Which quadratic equation can be used to determine the thickness of the frame, x? Image of a frame 7 feet wide by 8 feet long, with an of x on the bottom and right sides x2 + 15x − 2 = 0 x2 + 15x + 58 = 0 4x2 + 30x − 2 = 0 4x2 + 30x + 58 = 0
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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help_people
  • help_people
@jim_thompson5910
jim_thompson5910
  • jim_thompson5910
|dw:1442710030323:dw|
jim_thompson5910
  • jim_thompson5910
|dw:1442710064925:dw|

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More answers

jim_thompson5910
  • jim_thompson5910
can you tell me what this length is? |dw:1442710140915:dw|
help_people
  • help_people
15?
jim_thompson5910
  • jim_thompson5910
no the 7 is the vertical dimension I'm asking for the total horizontal dimension
jim_thompson5910
  • jim_thompson5910
hint: |dw:1442710233263:dw|
help_people
  • help_people
30?
jim_thompson5910
  • jim_thompson5910
idk how you're getting that
jim_thompson5910
  • jim_thompson5910
do you see the stuff I circled?
help_people
  • help_people
yes
jim_thompson5910
  • jim_thompson5910
add them up to get ???
help_people
  • help_people
2x or x^2
jim_thompson5910
  • jim_thompson5910
x + 8 + x = ???
help_people
  • help_people
7
jim_thompson5910
  • jim_thompson5910
think of it like this `apple + apple = 2 apples` so `x + x = 2x` right?
help_people
  • help_people
yeah x8x?
jim_thompson5910
  • jim_thompson5910
so if x+x = 2x, then x+x+8 turns into what?
help_people
  • help_people
2x+8
jim_thompson5910
  • jim_thompson5910
good
jim_thompson5910
  • jim_thompson5910
|dw:1442710945434:dw|
jim_thompson5910
  • jim_thompson5910
so hopefully you see how that total length marked in the drawing is 2x+8 feet?
help_people
  • help_people
i finally do :D
jim_thompson5910
  • jim_thompson5910
ok great
jim_thompson5910
  • jim_thompson5910
what is this marked length here? |dw:1442711082155:dw|
help_people
  • help_people
2x+7?
jim_thompson5910
  • jim_thompson5910
good
jim_thompson5910
  • jim_thompson5910
|dw:1442711337192:dw|
jim_thompson5910
  • jim_thompson5910
now if the length was 2x+8 and the width was 2x+7, then what is the area of the rectangle?
help_people
  • help_people
4x+15?
jim_thompson5910
  • jim_thompson5910
you have to multiply (2x+8) with (2x+7) FOIL it out
help_people
  • help_people
could you show me ?
jim_thompson5910
  • jim_thompson5910
have you learned the box method? that's actually better than FOIL
help_people
  • help_people
4x^2+30x+56?
jim_thompson5910
  • jim_thompson5910
good, you used the box method to get that? or some other method?
help_people
  • help_people
box method
jim_thompson5910
  • jim_thompson5910
ok great
jim_thompson5910
  • jim_thompson5910
so the entire area of the rectangle (larger rectangle) is `4x^2+30x+56` they tell us that "The painting and frame must have an area of 58 square feet." so equate the two areas 4x^2+30x+56 = 58
jim_thompson5910
  • jim_thompson5910
now get everything to one side
help_people
  • help_people
how
jim_thompson5910
  • jim_thompson5910
subtract 58 from both sides
jim_thompson5910
  • jim_thompson5910
|dw:1442712284053:dw|
jim_thompson5910
  • jim_thompson5910
|dw:1442712322065:dw|
jim_thompson5910
  • jim_thompson5910
|dw:1442712342649:dw|
help_people
  • help_people
4x^2+30x-2
help_people
  • help_people
@jim_thompson5910
jim_thompson5910
  • jim_thompson5910
correct
jim_thompson5910
  • jim_thompson5910
0 be left on the other side (since 58-58 = 0) so we have this answer `4x^2 + 30x - 2 = 0`
help_people
  • help_people
ok wow
help_people
  • help_people
tahnks alot for everything :)
jim_thompson5910
  • jim_thompson5910
no problem

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