A community for students.
Here's the question you clicked on:
 0 viewing
ineedhelp10
 one year ago
help! question written inside here
ineedhelp10
 one year ago
help! question written inside here

This Question is Closed

ineedhelp10
 one year ago
Best ResponseYou've already chosen the best response.0Find (f+g)(x),(fg)(x), (f*g)(x), and (f/g)(x) for each f(x) and g(x). State the domain of each new function. a. f(x)=x^2+4; g(x)=\[\sqrt{x}\]

ineedhelp10
 one year ago
Best ResponseYou've already chosen the best response.0b. f(x)= x7; g(x)=x+7

ineedhelp10
 one year ago
Best ResponseYou've already chosen the best response.0c. f(x)=\[\sqrt{x+8}; g(x)=\sqrt{x+5}3\]

ineedhelp10
 one year ago
Best ResponseYou've already chosen the best response.0\[d. f(x)= \frac{ 3 }{ x }; g(x)=x^4\]

ineedhelp10
 one year ago
Best ResponseYou've already chosen the best response.0im confused on this :/

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Find (f+g)(x),(fg)(x), (f*g)(x), and (f/g)(x) for each f(x) and g(x). State the domain of each new function. (f+g)(x) means add the 2 functions. Also written as f(x)+g(x) (fg)(x) subtract the 2 functions f(x)g(x) (f*g)(x) means multiply the 2 functions. Also written as f(x)*g(x) (f/g)(x) means divide f(x) by g(x). f(x)/g(x) Domain means all x values that work. Typical examples 1/x all numbers work except for numbers that make the denominator 0. In this case 0 1/(x+1) Here 1 wont work. SO all numbers except for 1 is domain Another type of domain example is sqrt(x) no numbers less than zero make it not work. So you can say domain is x>=0 >= Means greater or equal to zero

ineedhelp10
 one year ago
Best ResponseYou've already chosen the best response.0so then like for the first one im adding x^2 and \[\sqrt{x}\]

ineedhelp10
 one year ago
Best ResponseYou've already chosen the best response.0******x^2+4 i mean

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0(x^2+4)+(sqrt(x)) yes I like to use parenthesis at first

ineedhelp10
 one year ago
Best ResponseYou've already chosen the best response.0and what would the answer be? i didnt even know you could add those two together

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I dont think you can simplify a further so the domain is actually. x>=0

ineedhelp10
 one year ago
Best ResponseYou've already chosen the best response.0so for the addition, you dont do anything right just literally add them together correct?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0(fg)(x) same applies here.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You are correct. you will add them together if they are like terms like 2x+x=3x x^2+4x^2=5x^2 x+x+x+x=4x

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The odd pare is the multiplication part. (x^2+4)*(sqrt(x)) (sqrt(x))* (x^2+4) rearrange sqrt(x)*x^2+ 4*sqrt(x) distribute the sqrt (x) again domain will be x>=0 those are the only numbers that make it work. I dont think i even needed to distribute the sqrt(x) here. would still work

ineedhelp10
 one year ago
Best ResponseYou've already chosen the best response.0for the multiplication part i got \[x^2+4\sqrt{x}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0that looks wrong dude. I'll copy paste the right way from above The odd pare is the multiplication part. (x^2+4)*(sqrt(x)) (sqrt(x))* (x^2+4) rearrange sqrt(x)*x^2+ 4*sqrt(x) distribute the sqrt (x) again domain will be x>=0 those are the only numbers that make it work. I dont think i even needed to distribute the sqrt(x) here. would still work

ineedhelp10
 one year ago
Best ResponseYou've already chosen the best response.0kk bye thanks anyway!
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.