I need help with algebra ll hmwrk

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|dw:1442715709951:dw|
okay what about it ?what's the statement ?
Find the inverse

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f(x) is same as y so replace f(x) with y \[\huge\rm\color{ReD}{ y}=\frac{ -12-2\color{blue}{x} }{ 3 }\] to find inverse(f^{-1}(x)) `switch x and y` \[\huge\rm\color{blue}{ x}=\frac{ -12-2\color{red}{y} }{ 3 }\] now solve for y
im stuck lol
alright its okay what u got so fr
1 Attachment
Hows that lol
i have no idea what did you type into the calculator ??......
The problem you showed me
there isn't any radical in my comment not even exponent what are you talking about ? o.O
|dw:1442716563503:dw|\(\color{blue}{\text{Originally Posted by}}\) @Nnesha f(x) is same as y so replace f(x) with y \[\huge\rm\color{ReD}{ y}=\frac{ -12-2\color{blue}{x} }{ 3 }\] to find inverse(f^{-1}(x)) `switch x and y` \[\huge\rm\color{blue}{ x}=\frac{ -12-2\color{red}{y} }{ 3 }\] now solve for y \(\color{blue}{\text{End of Quote}}\)
i put the x= one into wolf fram
do you know how to solve that equation for y ?
first we nee to get rid of the denominator at right side so multiply both sides by 3
substitute y for f(x) then solve x in terms of y then switch x and y and then replace the y with f^-1(x)
yes right so how would you solve x in terms of y ?
\[\huge\rm\color{blue}{ x}=\frac{ -12-2\color{red}{y} }{ 3 }\] first multiply both sides by 3
ok so 3x-12 or
\[\huge\rm\color{green}{3}·\color{blue}{ x}=\frac{ -12-2\color{red}{y} }{\cancel{ 3} }·\color{green}{\cancel{3}}\] multiply both sides by 3 at right side 3 cancels out then u get \[\huge\rm 3x=-12-2y\] now move the -12 at left side how would you do that would add ,subtract,multiply or divide 12 both sides ?
multiply
hmm no it's `-12 -2y` -12 is subtracting with -2y so you should apply the opposite of `subtraction` which is addition so add 12 both sides
ok add negative 12 to both or positive
it's negative 12 at right side so what is opposite of negative ?
positive
yes so to cancel out -12 you should add
yea
|dw:1442717916498:dw| let me know what you get
DON"t add 3x and 12 it's not 15 okay! :=)
Ok
ok well 12 and 12 make 24
|dw:1442718071794:dw|
oh
0
to solve for y we need to move -12 and -2 to the left side so we should cancel out the 12
and you can't add 3x with -12 so that would stay the same |dw:1442718149403:dw|
now one and last step cancel out the -2 from right side how would you do that ?
{-3x-12}/{2}
it's -2 · y (multiplication) apply the opposite of multiplication
oh never mind good job!
\[y=\frac{ -3x-12 }{ 2 } =\] is same as \[y=\frac{ -3 x}{ 2 } -\frac{ 12 }{ 2 }\] you can divide 12/2
lol yea i just started school so we are now started doing these and i got a 2/26 on my review and
okay got 2 mints divide 12/2 = ?
oh 6
yes so \[y=\frac{ -3 x}{ 2 } -6\]
and let me tell you how to put that inot the calculator x=(-12-2y)/3 (PARENTHESES FOR SAFETY
oh ok ^-^

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