I need help with algebra ll hmwrk

- geekfromthefutur

I need help with algebra ll hmwrk

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- geekfromthefutur

|dw:1442715709951:dw|

- Nnesha

okay what about it ?what's the statement ?

- geekfromthefutur

Find the inverse

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## More answers

- Nnesha

f(x) is same as y so replace f(x) with y
\[\huge\rm\color{ReD}{ y}=\frac{ -12-2\color{blue}{x} }{ 3 }\]
to find inverse(f^{-1}(x)) `switch x and y`
\[\huge\rm\color{blue}{ x}=\frac{ -12-2\color{red}{y} }{ 3 }\]
now solve for y

- geekfromthefutur

im stuck lol

- Nnesha

alright its okay what u got so fr

- geekfromthefutur

##### 1 Attachment

- geekfromthefutur

Hows that lol

- Nnesha

i have no idea
what did you type into the calculator ??......

- geekfromthefutur

The problem you showed me

- Nnesha

there isn't any radical in my comment not even exponent
what are you talking about ? o.O

- Nnesha

|dw:1442716563503:dw|\(\color{blue}{\text{Originally Posted by}}\) @Nnesha
f(x) is same as y so replace f(x) with y
\[\huge\rm\color{ReD}{ y}=\frac{ -12-2\color{blue}{x} }{ 3 }\]
to find inverse(f^{-1}(x)) `switch x and y`
\[\huge\rm\color{blue}{ x}=\frac{ -12-2\color{red}{y} }{ 3 }\]
now solve for y
\(\color{blue}{\text{End of Quote}}\)

- geekfromthefutur

i put the x= one into wolf fram

- Nnesha

do you know how to solve that equation for y ?

- Nnesha

first we nee to get rid of the denominator at right side
so multiply both sides by 3

- geekfromthefutur

substitute y for f(x) then solve x in terms of y then switch x and y and then replace the y with f^-1(x)

- Nnesha

yes right so how would you solve x in terms of y ?

- Nnesha

\[\huge\rm\color{blue}{ x}=\frac{ -12-2\color{red}{y} }{ 3 }\]
first multiply both sides by 3

- geekfromthefutur

ok so 3x-12 or

- Nnesha

\[\huge\rm\color{green}{3}·\color{blue}{ x}=\frac{ -12-2\color{red}{y} }{\cancel{ 3} }·\color{green}{\cancel{3}}\]
multiply both sides by 3
at right side 3 cancels out
then u get \[\huge\rm 3x=-12-2y\]
now move the -12 at left side
how would you do that would add ,subtract,multiply or divide 12 both sides ?

- geekfromthefutur

multiply

- Nnesha

hmm no it's `-12 -2y`
-12 is subtracting with -2y
so you should apply the opposite of `subtraction` which is addition
so add 12 both sides

- geekfromthefutur

ok add negative 12 to both or positive

- Nnesha

it's negative 12 at right side so what is opposite of negative ?

- geekfromthefutur

positive

- Nnesha

yes so to cancel out -12 you should add

- geekfromthefutur

yea

- Nnesha

|dw:1442717916498:dw|
let me know what you get

- Nnesha

DON"t add 3x and 12
it's not 15 okay! :=)

- geekfromthefutur

Ok

- geekfromthefutur

ok well 12 and 12 make 24

- Nnesha

|dw:1442718071794:dw|

- geekfromthefutur

oh

- geekfromthefutur

0

- Nnesha

to solve for y we need to move -12 and -2 to the left side so we should cancel out the 12

- Nnesha

and you can't add 3x with -12 so that would stay the same |dw:1442718149403:dw|

- Nnesha

now one and last step
cancel out the -2 from right side
how would you do that ?

- geekfromthefutur

{-3x-12}/{2}

- Nnesha

it's -2 · y (multiplication)
apply the opposite of multiplication

- Nnesha

oh never mind good job!

- Nnesha

\[y=\frac{ -3x-12 }{ 2 } =\] is same as \[y=\frac{ -3 x}{ 2 } -\frac{ 12 }{ 2 }\] you can divide 12/2

- geekfromthefutur

lol yea i just started school so we are now started doing these and i got a 2/26 on my review and

- Nnesha

okay got 2 mints
divide 12/2 = ?

- geekfromthefutur

oh 6

- Nnesha

yes so \[y=\frac{ -3 x}{ 2 } -6\]

- Nnesha

and let me tell you how to put that inot the calculator
x=(-12-2y)/3 (PARENTHESES FOR SAFETY

- geekfromthefutur

oh ok ^-^

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