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anonymous
 one year ago
[Statistics] A production facility employs 10 workers on the day shift, 8 workers on the swing shift, and 6 workers on the graveyard shift. A quality control consultant is to select 4 of these workers for indepth interviews. Suppose the selection is made in such a way that any particular group of 4 workers has the same chance of being selected as does any other group
anonymous
 one year ago
[Statistics] A production facility employs 10 workers on the day shift, 8 workers on the swing shift, and 6 workers on the graveyard shift. A quality control consultant is to select 4 of these workers for indepth interviews. Suppose the selection is made in such a way that any particular group of 4 workers has the same chance of being selected as does any other group

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0What is the probability that one of the shifts will be unrepresented in the sample of workers?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I got that there are (24)(23)(22)(21)/(4)(3)(2) = 10626 possibilities (18)(17)(16)(15)/(4)(3)(2) = 3060 possibilities where graveyard is unrepresented (16)(15)(14)(13)/(4)(3)(2) = 1820 possibilities where swing is unrepresented (14)(13)(12)(11)/(4)(3)(2) = 1001 possibilities where day is unrepresented So the total probability is (3060+1820+1001)/10626 = .5535, which is incorrect.
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