zuha
  • zuha
Graph quadrilateral JKLM with Vertices J(-3,-3), K(1,-3), L(1,4), and M(-3, 1). What is the perimeter of JKLM?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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EmmaTassone
  • EmmaTassone
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EmmaTassone
  • EmmaTassone
Just graph the points and join them with lines,then you will get the quadrilateral.
EmmaTassone
  • EmmaTassone
After that to calculate the perimeter you have to sum every side of the quadrilateral. So first you need the lenght of each side to sum them.

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zuha
  • zuha
Yeah, so KL=7 JK=4 JM=4 and LM=2.6 which equals 17 .6 for me
EmmaTassone
  • EmmaTassone
how did you get the lenght?
zuha
  • zuha
4(-3)=7, 1-(-3)=4, -3-1=4, sqrt(1-4)^2+(-3-1)^2
EmmaTassone
  • EmmaTassone
and how did you get 2.6 for LM?
zuha
  • zuha
The last one sqrt(1-4)^2+(-3-1)^2
EmmaTassone
  • EmmaTassone
yep, but you did it wrong.
zuha
  • zuha
Oh .-. Ah. Yeah ;v;. How so?
EmmaTassone
  • EmmaTassone
\[\sqrt{(1-4)^{2}+(-1-3)^{2})}= \sqrt{(-3)^2+(-4)^2} = \sqrt{9 + 16} = \sqrt{25} = 5\]
EmmaTassone
  • EmmaTassone
thats the way how you should solve the square root
zuha
  • zuha
Ahhhh, so I wrote 4 instead of -4 and it wrecked everything :) Thanks, got it
EmmaTassone
  • EmmaTassone
equally you got the solution because of luck xD because thats not the formula to find the length between two points. The true formula for two points (a1,b1) and (a2,b2) in the plane is:\[Lenght= \sqrt{(a _{1}-a _{2})^2+(b _{1}-b _{2})^2}\]
EmmaTassone
  • EmmaTassone
Hope it helps

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