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zuha

  • one year ago

Graph quadrilateral JKLM with Vertices J(-3,-3), K(1,-3), L(1,4), and M(-3, 1). What is the perimeter of JKLM?

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  1. EmmaTassone
    • one year ago
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    |dw:1442726140497:dw|

  2. EmmaTassone
    • one year ago
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    Just graph the points and join them with lines,then you will get the quadrilateral.

  3. EmmaTassone
    • one year ago
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    After that to calculate the perimeter you have to sum every side of the quadrilateral. So first you need the lenght of each side to sum them.

  4. Zuha
    • one year ago
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    Yeah, so KL=7 JK=4 JM=4 and LM=2.6 which equals 17 .6 for me

  5. EmmaTassone
    • one year ago
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    how did you get the lenght?

  6. Zuha
    • one year ago
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    4(-3)=7, 1-(-3)=4, -3-1=4, sqrt(1-4)^2+(-3-1)^2

  7. EmmaTassone
    • one year ago
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    and how did you get 2.6 for LM?

  8. Zuha
    • one year ago
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    The last one sqrt(1-4)^2+(-3-1)^2

  9. EmmaTassone
    • one year ago
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    yep, but you did it wrong.

  10. Zuha
    • one year ago
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    Oh .-. Ah. Yeah ;v;. How so?

  11. EmmaTassone
    • one year ago
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    \[\sqrt{(1-4)^{2}+(-1-3)^{2})}= \sqrt{(-3)^2+(-4)^2} = \sqrt{9 + 16} = \sqrt{25} = 5\]

  12. EmmaTassone
    • one year ago
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    thats the way how you should solve the square root

  13. Zuha
    • one year ago
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    Ahhhh, so I wrote 4 instead of -4 and it wrecked everything :) Thanks, got it

  14. EmmaTassone
    • one year ago
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    equally you got the solution because of luck xD because thats not the formula to find the length between two points. The true formula for two points (a1,b1) and (a2,b2) in the plane is:\[Lenght= \sqrt{(a _{1}-a _{2})^2+(b _{1}-b _{2})^2}\]

  15. EmmaTassone
    • one year ago
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    Hope it helps

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