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Diana.xL

  • one year ago

help?

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  1. Diana.xL
    • one year ago
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    http://prntscr.com/8icohg

  2. zzr0ck3r
    • one year ago
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    Post the question where you put "help?"

  3. zzr0ck3r
    • one year ago
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    and ideas?

  4. Diana.xL
    • one year ago
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    my answer is b. but im confused.

  5. anonymous
    • one year ago
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    Yeah, B is the answer. What confuses you?

  6. zzr0ck3r
    • one year ago
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    almost, you do want to square root both sides, but when we induce the square, we get a positive and negative answer.

  7. zzr0ck3r
    • one year ago
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    the answer is not B

  8. Diana.xL
    • one year ago
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    oh right

  9. anonymous
    • one year ago
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    If 16 is X squared, then X is the square root of 16. Ok, now I'm confused.

  10. Diana.xL
    • one year ago
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    so it would be c yea?

  11. anonymous
    • one year ago
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    I swear it's B!

  12. zzr0ck3r
    • one year ago
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    i.e. \[(-4)^2=(-4)(-4)=16=4*4=4^2=\]

  13. anonymous
    • one year ago
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    Confusion is occuring.

  14. anonymous
    • one year ago
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    I don't know what I'm doing it appears. I'm just gonig to go because this seems to be much more complicated than I thought :I

  15. zzr0ck3r
    • one year ago
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    the answer to \(x=\sqrt{16}\) is \(x=4\) The answer to \(x^2=16\) is \(x=\pm 4\)

  16. zzr0ck3r
    • one year ago
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    @FitzIncorporated it is a common mistake. when we write \(\sqrt{something}\) we mean the positive square root(just like if we write 1). But when we induce a square (when we take square root of both sides) we get two answers. In other words, the square root of 4 is 2 but there are two answers if I ask you what number squared is 4, they are 2 and -2

  17. Diana.xL
    • one year ago
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    so its c? its lagging a bit

  18. CGGURUMANJUNATH
    • one year ago
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    C

  19. Diana.xL
    • one year ago
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    okTy :)

  20. anonymous
    • one year ago
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    @zzr0ck3r Thank you :)

  21. zzr0ck3r
    • one year ago
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    for sure :)

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