1018
  • 1018
A thin rod with mass M = 5.99 kg is bent in a semicircle of radius R = 0.603 m (the figure below). (a) What is its gravitational force (both magnitude and direction) on a particle with mass m = 4.65×10^(-3) kg at P, the center of curvature? (b) What would be the force on the particle if the rod were a complete circle?
Mathematics
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions.

1018
  • 1018
A thin rod with mass M = 5.99 kg is bent in a semicircle of radius R = 0.603 m (the figure below). (a) What is its gravitational force (both magnitude and direction) on a particle with mass m = 4.65×10^(-3) kg at P, the center of curvature? (b) What would be the force on the particle if the rod were a complete circle?
Mathematics
jamiebookeater
  • jamiebookeater
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

1018
  • 1018
wasn't able to attend my lecture on laws of gravitation, so I ask for help. haha. thanks
IrishBoy123
  • IrishBoy123
|dw:1442743273315:dw|use symmetry in y axis in the x axis, for an easy derivation go to p138 of this https://books.google.co.uk/books?id=DrTecfmiVnAC&pg=PA138&lpg=PA138&dq=gravitational+attraction+semi+circle+mass&source=bl&ots=GOFVqr1CAa&sig=yx6bzZh2pAPExOkwqFbqZDN9gL0&hl=en&sa=X&ved=0CC8Q6AEwAmoVChMI-LCSvKuFyAIV42vbCh31GgmE#v=onepage&q=gravitational%20attraction%20semi%20circle%20mass&f=false formula is there too.
IrishBoy123
  • IrishBoy123
gtg or i would do more now

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

1018
  • 1018
thank you! I'll try to take it from here.

Looking for something else?

Not the answer you are looking for? Search for more explanations.