anonymous
  • anonymous
Why does n*log(-a) != log([-a]^n). For example, suppose n = 2, and a =4.
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
\[n \log (-a) \neq \log([-a]^n)\] e.g. n =2, a = 4 \[n \log (-a) \neq \log([-a]^n)\] \[2 \log (-4) \neq \log([-4]^2)\] \[2 \log (-4) \neq \log(16)\] LHS is undefined and right hand side has a value. Why do the log laws not seem to work in this case?
Empty
  • Empty
The reason is you're assuming \(a\) is a negative number and then plugging in a positive number. It will work if you plug in negative values for a.
Empty
  • Empty
Ok ok, maybe that's kind of a cheap answer, so I'll say it another way: \[\log(4)=\log((-2)^2)\ne2\log(-2)\] So unfortunately negative numbers in logarithms are mostly nonsense, but you can find answers for what they mean if you are working with complex numbers. But at that point, then you will find that the logarithm is really multi-valued!

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

zzr0ck3r
  • zzr0ck3r
i agree. you put in positive on the rhs, but the lhs is undefined in the example It is sort of like starting with 2=3 and then concluding that 1=0 and then questioning addition
anonymous
  • anonymous
Thanks guys, so the law just basically assumes that a and n are positive.

Looking for something else?

Not the answer you are looking for? Search for more explanations.