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nosnip
 one year ago
Quadratic simultaneous equation PLEASE help me
nosnip
 one year ago
Quadratic simultaneous equation PLEASE help me

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nosnip
 one year ago
Best ResponseYou've already chosen the best response.0\[y= x4\] \[2x ^{2} xy = 8\] Give your answer in the form a±b sqrt(c)

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2replace the y in the second equation by x  4 to form a quadratic in x

nosnip
 one year ago
Best ResponseYou've already chosen the best response.0It says I have to use elimination though?

nosnip
 one year ago
Best ResponseYou've already chosen the best response.0Should I make y the subject of both of them and then minus them?

Hero
 one year ago
Best ResponseYou've already chosen the best response.1Multiply the first equation by x

nosnip
 one year ago
Best ResponseYou've already chosen the best response.0So you get \[x ^{2}  xy  4x = 0\] \[2x ^{2}  xy  8 = 0\] Is that right?

nosnip
 one year ago
Best ResponseYou've already chosen the best response.0And then you have to minus them?

Hero
 one year ago
Best ResponseYou've already chosen the best response.1What you want to do is setup the equations in a way where you can combine both together and eliminate the xy term . I try to setup to add rather than subtract

nosnip
 one year ago
Best ResponseYou've already chosen the best response.0So if the plus and minus signs were all reversed and x^2 and 2x^2 were both negative owuld that be better?

nosnip
 one year ago
Best ResponseYou've already chosen the best response.0Got it thankyou so much :)

nosnip
 one year ago
Best ResponseYou've already chosen the best response.0Well it was a "prove that..." question and I got x^2 +4x  8 which is what we had to prove so thanks :)

Hero
 one year ago
Best ResponseYou've already chosen the best response.1I thought you had to solve for x in the form a±b sqrt(c)

nosnip
 one year ago
Best ResponseYou've already chosen the best response.0No that was a mistake I have to prove
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