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anonymous

  • one year ago

Uniform Circular Motion/Law of Gravitational Problem need help badly

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  1. anonymous
    • one year ago
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  2. anonymous
    • one year ago
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    GG PHY10 waa ang hirap haha

  3. anonymous
    • one year ago
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    First think broadly (conceptually). Which side of A do you think you would need a mass in order to produce a gravitational force on A which would counter act (balance) the gravitational forces on A caused by B and C? Next you must calculate. I would analyze the forces acting on A with a free body diagram (you only are asked to find Fnet= 0 for particle A (that is what "no net gravitational force" is saying). Force of gravity on A caused by B is in the +y direction and the force of gravity on A caused by C is in the -x direction. You must create a gravitational force (by choosing where to place your D mass (4.00ma) that will simultaneously cancel our those two forces (hint: the force of gravity on A caused by D will have both x and y components). Hope that helps.

  4. MrNood
    • one year ago
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    you can treat the x and y component separately the x force of the new mass will be 4m/x^2 (where x is its x coordinate) this has to cancel the force from particle c (=3m/1.5^2) so you can solve for x do the same for y

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