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imqwerty

  • one year ago

number fun ( ͡° ͜ʖ ͡°)

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  1. imqwerty
    • one year ago
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    l,m,n are positive real numbers such that \[l^3+m^3=n^3\]prove that \[l^2+m^2-n^2>6(n-l)(n-m)\]

  2. anonymous
    • one year ago
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    i^2+m^2-(i^2+m^2)>6((i+m)-l)((i+m)-m) 0>6(m+i)

  3. Kainui
    • one year ago
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    if \(l>n\) or \(m>n\) then the left side of the inequality is a positive number and the right side is a negative number. if \(l>n\) and \(m>n\) then the right hand side will be positive, so I have no proof, oh well, sorry. if \(l<n\) and \(m<n\) then I also have no proof so I guess I just wasted my time, but hey I proved it for like infinitely number of cases as long as this is true, the inequality will be true: \[l<n<m\] Haha oh well. I just wanna avoid playing with binomial expansions xD

  4. anonymous
    • one year ago
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    stalker

  5. anonymous
    • one year ago
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    >.>

  6. imqwerty
    • one year ago
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    :)

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