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anonymous

  • one year ago

Jane only bake cakes on Saturday and her customers must preorder them. Because of the constraint of her kitchen and oven she could only bake 10 cakes. Through past experience 85% of her customers honour their order. To minimize lost of profit she will accept 12 orders. She will have to disappoint her 11th and 12th customers if all decided to honour their orders. What is that probability? What is the expected number of customers she will disappoint? What assumptions you need to assume to perform your calculation?

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  1. anonymous
    • one year ago
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    Hi, do you understand a little bit of what the problem wants or none at all?

  2. anonymous
    • one year ago
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    Hi @Felicity214 Hmm best to assume none at all, I only just started learning about random variable and expected value.

  3. anonymous
    • one year ago
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    What level of math is this for?

  4. anonymous
    • one year ago
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    A college introductory statistic class, a practice problem. Under section random variables, expected value.

  5. anonymous
    • one year ago
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    Wow. Not on that level yet. I'm just taking algebra rwo

  6. anonymous
    • one year ago
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    sorry, I guess that means I can't help. Why don't you place this in the qualified helper section?

  7. anonymous
    • one year ago
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    Qualified helper need money I guess

  8. anonymous
    • one year ago
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    YEP

  9. anonymous
    • one year ago
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    do you by any chance know french?

  10. anonymous
    • one year ago
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    because i need help.

  11. anonymous
    • one year ago
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    I studied french before but it is a long time ago and I got a bad grade of B-

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spraguer (Moderator)
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