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anonymous

  • one year ago

Decide which part of the quadratic formula tells you whether the quadratic equation can be solved by factoring. −b b2 − 4ac 2a Use the part of the quadratic formula that you chose above and find its value, given the following quadratic equation: 2x2 + 7x + 3 = 0

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  1. pooja195
    • one year ago
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    \(b^2-4ac\) is called 'Discriminant' which decides that whether the the quadratic equation can be solved by factoring.

  2. anonymous
    • one year ago
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    I know that

  3. pooja195
    • one year ago
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    So you need help factoring?

  4. anonymous
    • one year ago
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    Basically

  5. pooja195
    • one year ago
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    Well what numbers multiply to make 6 but add to make 7?

  6. anonymous
    • one year ago
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    6 and 1

  7. anwaarullah
    • one year ago
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    2x^+6x+x+3=0

  8. pooja195
    • one year ago
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    ok now you have (2x+6 )(2x+1) Can you divide both of these by a GCF?

  9. pooja195
    • one year ago
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    What number can we divide 2 and 6 by?

  10. anonymous
    • one year ago
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    2

  11. anwaarullah
    • one year ago
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    take common

  12. pooja195
    • one year ago
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    You cant simpyfy anything more so you have 2x+3=0 2x+1=0 solve both for x

  13. anwaarullah
    • one year ago
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    |dw:1442766320422:dw| solve more

  14. anonymous
    • one year ago
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    x=-3/2 and x=-1/2

  15. pooja195
    • one year ago
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    -1/2 is right the other one is incorrect

  16. anwaarullah
    • one year ago
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    x+3=0 ?????

  17. pooja195
    • one year ago
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    @anwaarullah its my mistake i wrote it wrong.

  18. pooja195
    • one year ago
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    \(\color{#0cbb34}{\text{Originally Posted by}}\) @pooja195 You cant simpyfy anything more so you have 2x+3=0 2x+1=0 solve both for x \(\color{#0cbb34}{\text{End of Quote}}\) it shouldve been x+3=0

  19. anonymous
    • one year ago
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    x=-3

  20. anonymous
    • one year ago
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    for the questions, numerical answers are expected sorry forgot to say that

  21. pooja195
    • one year ago
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    Good \[ x+3=0:\quad x=-3\] \[2x+1=0:\quad x=-\frac{1}{2} \]

  22. pooja195
    • one year ago
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    This is numerical

  23. anonymous
    • one year ago
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    supposedly for this, one answer is needed

  24. pooja195
    • one year ago
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    oh ok i see what they wanted

  25. pooja195
    • one year ago
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    we need to set this equal to y since we are solviing using the discernment \[\huge~\rm~y=2x^2+7x+3 \]

  26. pooja195
    • one year ago
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    \[\huge~\rm~~discriminant=b^2−4(a)(c) \]

  27. pooja195
    • one year ago
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    \[\huge~\rm~7^2−4(2)(3) =? \]

  28. anonymous
    • one year ago
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    25

  29. pooja195
    • one year ago
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    Yep there we go :)

  30. anonymous
    • one year ago
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    that is what i had from the beginning just wasn't sure

  31. pooja195
    • one year ago
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    ah ok sorry for making things more complicated than they needed to be!

  32. anonymous
    • one year ago
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    its fine

  33. pooja195
    • one year ago
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    \(~~~~~~~~~~~~~~~~~~~~~~~~~~\Huge{\color{red}{\heartsuit}\color{orange}{\bigstar}\color{yellow}{\heartsuit}\color{green}{\bigstar}\color{blue}{\heartsuit}\color{purple}{\bigstar}\color{hotpink}{\heartsuit}}\)\(\Huge\bf\color{#FF0000}W\color{#FF4900}e\color{#FF9200}l\color{#FFDB00}c\color{#FFff00}o\color{#B6ff00}m\color{#6Dff00}e\color{#24ff00}~\color{#00ff00}t\color{#00ff49}o\color{#00ff92}~\color{#00ffDB}O\color{#00ffff}p\color{#00DBff}e\color{#0092ff}n\color{#0049ff}S\color{#0000ff}t\color{#2400ff}u\color{#6D00ff}d\color{#B600ff}y\color{#FF00ff}!\)\(~~~~~~~~~~~~~~~~~~~~~~~~~~\Huge{\color{red}{\heartsuit}\color{orange}{\bigstar}\color{yellow}{\heartsuit}\color{green}{\bigstar}\color{blue}{\heartsuit}\color{purple}{\bigstar}\color{hotpink}{\heartsuit}}\)\(\Large\bf\color{Lime}{Please,\ don't\ hesitate\ to\ ask\ questions!}\)\(\Large\bf\color{magenta}{We're\ here\ to\ help!}\Large\color{magenta}{\ddot\smile}\)

  34. anonymous
    • one year ago
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    :) thanks

  35. pooja195
    • one year ago
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    :)

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