Decide which part of the quadratic formula tells you whether the quadratic equation can be solved by factoring. −b b2 − 4ac 2a Use the part of the quadratic formula that you chose above and find its value, given the following quadratic equation: 2x2 + 7x + 3 = 0

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Decide which part of the quadratic formula tells you whether the quadratic equation can be solved by factoring. −b b2 − 4ac 2a Use the part of the quadratic formula that you chose above and find its value, given the following quadratic equation: 2x2 + 7x + 3 = 0

Mathematics
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\(b^2-4ac\) is called 'Discriminant' which decides that whether the the quadratic equation can be solved by factoring.
I know that
So you need help factoring?

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Other answers:

Basically
Well what numbers multiply to make 6 but add to make 7?
6 and 1
2x^+6x+x+3=0
ok now you have (2x+6 )(2x+1) Can you divide both of these by a GCF?
What number can we divide 2 and 6 by?
2
take common
You cant simpyfy anything more so you have 2x+3=0 2x+1=0 solve both for x
|dw:1442766320422:dw| solve more
x=-3/2 and x=-1/2
-1/2 is right the other one is incorrect
x+3=0 ?????
@anwaarullah its my mistake i wrote it wrong.
\(\color{#0cbb34}{\text{Originally Posted by}}\) @pooja195 You cant simpyfy anything more so you have 2x+3=0 2x+1=0 solve both for x \(\color{#0cbb34}{\text{End of Quote}}\) it shouldve been x+3=0
x=-3
for the questions, numerical answers are expected sorry forgot to say that
Good \[ x+3=0:\quad x=-3\] \[2x+1=0:\quad x=-\frac{1}{2} \]
This is numerical
supposedly for this, one answer is needed
oh ok i see what they wanted
we need to set this equal to y since we are solviing using the discernment \[\huge~\rm~y=2x^2+7x+3 \]
\[\huge~\rm~~discriminant=b^2−4(a)(c) \]
\[\huge~\rm~7^2−4(2)(3) =? \]
25
Yep there we go :)
that is what i had from the beginning just wasn't sure
ah ok sorry for making things more complicated than they needed to be!
its fine
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:) thanks
:)

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