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anonymous

  • one year ago

This may just be a forgetful moment on my part, but could someone please explain to me how you get...

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  1. anonymous
    • one year ago
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    \[f(x)=3x^2+2\] from \[3x^2+3x \Delta x+ \Delta x^2+2\] by substituting the limit (0) into the equation?

  2. anonymous
    • one year ago
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    I'm learning derivatives if that helps explain anything.

  3. ZeHanz
    • one year ago
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    The limit means \(\Delta x \) becomes smalles and smaller. Now, 3x has a certain value, once you have chosen the x. Imagine what happens with the term \(3x \cdot \Delta x\): you have to multiply this certain value of 3x with an ever smaller number: it becoms vanishingly small, in fact it goes to 0. Same happens to \( (\Delta x)^2\), leaving you with \(3x^2 + 2\).

  4. anonymous
    • one year ago
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    So only the \[x \Delta\] will be substituted with the 0, correct?

  5. amistre64
    • one year ago
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    yes

  6. anonymous
    • one year ago
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    Is there a particular reason why? (sorry, but if i know why it helps me remember to do it)

  7. anonymous
    • one year ago
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    Oops! Never mind! I see now. Thank you.

  8. ZeHanz
    • one year ago
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    yw!

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