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anonymous
 one year ago
This may just be a forgetful moment on my part, but could someone please explain to me how you get...
anonymous
 one year ago
This may just be a forgetful moment on my part, but could someone please explain to me how you get...

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[f(x)=3x^2+2\] from \[3x^2+3x \Delta x+ \Delta x^2+2\] by substituting the limit (0) into the equation?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'm learning derivatives if that helps explain anything.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The limit means \(\Delta x \) becomes smalles and smaller. Now, 3x has a certain value, once you have chosen the x. Imagine what happens with the term \(3x \cdot \Delta x\): you have to multiply this certain value of 3x with an ever smaller number: it becoms vanishingly small, in fact it goes to 0. Same happens to \( (\Delta x)^2\), leaving you with \(3x^2 + 2\).

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So only the \[x \Delta\] will be substituted with the 0, correct?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Is there a particular reason why? (sorry, but if i know why it helps me remember to do it)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oops! Never mind! I see now. Thank you.
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