anonymous
  • anonymous
This may just be a forgetful moment on my part, but could someone please explain to me how you get...
Mathematics
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katieb
  • katieb
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anonymous
  • anonymous
\[f(x)=3x^2+2\] from \[3x^2+3x \Delta x+ \Delta x^2+2\] by substituting the limit (0) into the equation?
anonymous
  • anonymous
I'm learning derivatives if that helps explain anything.
ZeHanz
  • ZeHanz
The limit means \(\Delta x \) becomes smalles and smaller. Now, 3x has a certain value, once you have chosen the x. Imagine what happens with the term \(3x \cdot \Delta x\): you have to multiply this certain value of 3x with an ever smaller number: it becoms vanishingly small, in fact it goes to 0. Same happens to \( (\Delta x)^2\), leaving you with \(3x^2 + 2\).

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anonymous
  • anonymous
So only the \[x \Delta\] will be substituted with the 0, correct?
amistre64
  • amistre64
yes
anonymous
  • anonymous
Is there a particular reason why? (sorry, but if i know why it helps me remember to do it)
anonymous
  • anonymous
Oops! Never mind! I see now. Thank you.
ZeHanz
  • ZeHanz
yw!

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