anonymous
  • anonymous
....
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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amistre64
  • amistre64
what is our derivative of f wrt.x?
anonymous
  • anonymous
2-2cos(2x)
amistre64
  • amistre64
+ not - factor out the 2 and ... what do you see that we can do then?

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amistre64
  • amistre64
or set it equal to 0, subtract off the 2, divide by -2 etc ...
anonymous
  • anonymous
You get 2(1-cosx)
amistre64
  • amistre64
2(1 + cos(2x)) = 0 since 2 is never 0, that only leaves 1+cos(2x) to be zero for this to have any chance of working
amistre64
  • amistre64
when does 1+cos(2x) = 0?
anonymous
  • anonymous
At 0?
amistre64
  • amistre64
no cos(0) = 1, not -1
amistre64
  • amistre64
cos(2x) = -1 is what we want for 1 + cos(2x) to be zero
amistre64
  • amistre64
cos(pi) = -1, so when does 2x = pi?
amistre64
  • amistre64
cos(3pi) = -1 as well, any odd multiple of pi makes cos go to -1 2x = 3pi should fit in the interval if i see it correctly
anonymous
  • anonymous
Thats the answer?
amistre64
  • amistre64
those are approaches that I would take to find the answer ...
anonymous
  • anonymous
Which do you think is the best approach
amistre64
  • amistre64
ive only given 1 approach
amistre64
  • amistre64
given that our interval is from x=0 to pi 2x gives us a range from 0 to 4pi to play with cos(pi) and cos(3pi) are both equal to -1 so we will have 2 solutions.
amistre64
  • amistre64
2x= pi, and 2x = 3pi
amistre64
  • amistre64
** our interval is x=0 to 2pi ...
anonymous
  • anonymous
So x=pi/2 and x=3/2pi
amistre64
  • amistre64
correct
anonymous
  • anonymous
Thank you!!!

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