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anonymous

  • one year ago

y=3^(2(x-3))+1 sketch and properly label the toolkit function, then perform the transformations in the correct order, and sketch and label the transformation function

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  1. anonymous
    • one year ago
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    @amistre64

  2. amistre64
    • one year ago
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    this seems to be an application of some text specific method ....

  3. anonymous
    • one year ago
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    graphing the toolkit function

  4. anonymous
    • one year ago
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    and then do horizontal/vertical transformations

  5. amistre64
    • one year ago
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    y= 3^x shift right by 3 stretch horizontally by a factor of 2 then move up by 1 seems to be the process

  6. anonymous
    • one year ago
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    so would it be that i graph y=3^x

  7. amistre64
    • one year ago
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    start with y=3^x yes

  8. anonymous
    • one year ago
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    so (-2, 1/9), (-1, 1/3), (0, 1), (1, 3), 2,9

  9. amistre64
    • one year ago
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    those are points on 3^x yes

  10. amistre64
    • one year ago
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    now add 3 to your x values

  11. amistre64
    • one year ago
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    |dw:1442776104923:dw| at x=3, we should represent the value at x=0, since x-3 = 0 when x=3

  12. amistre64
    • one year ago
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    (-2+3, 1/9) (-1+3, 1/3) (0+3, 1) (1+3, 3) (2+3, 9) (1, 1/9) (2, 1/3) (3, 1) (4, 3) (5, 9) now double your xs (2*1, 1/9) (2*2, 1/3) (2*3, 1) (2*4, 3) (2*5, 9) (2, 1/9) (4, 1/3) (6, 1) (8, 3) (10, 9) now we alter the y parts, by +1

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