A community for students.
Here's the question you clicked on:
 0 viewing
korosh23
 one year ago
Pressure can be used only for gaseous reactants?
Does it mean all the reactants have to be gaseous?
korosh23
 one year ago
Pressure can be used only for gaseous reactants? Does it mean all the reactants have to be gaseous?

This Question is Closed

korosh23
 one year ago
Best ResponseYou've already chosen the best response.1For example, C(s) + O2 > CO2 (g) Can pressure affect this heterogeneous reaction or do all the reactants need to be gaseous?

Photon336
 one year ago
Best ResponseYou've already chosen the best response.1\[C(s) + O_{2}(g) > CO_{2}(g) \]

korosh23
 one year ago
Best ResponseYou've already chosen the best response.1Yes, as we know we have two words in chemistry. Total pressure of the system or partial pressure of a gas.

Photon336
 one year ago
Best ResponseYou've already chosen the best response.1well for a gaseous reaction it depends on the partial pressure exerted by each gas

Photon336
 one year ago
Best ResponseYou've already chosen the best response.1couple of things here to explain

Photon336
 one year ago
Best ResponseYou've already chosen the best response.1the first is that whenever you have a container of gases the pressure exerted by each individual gas will be proportional to the mole fraction of that gas. say you have 1 mole of A and 2 moles of B both gases first we find out how many total moles of gas we have that's 1+2 = 3 moles of gas. A + 2B > AB_{2} and the pressure is 1 atm \[Gas_{A} \frac{ 1 }{ 2 }*1atm + Gas_{B}\frac{ 2 }{ 3 }*1atm = total pressure \]

Photon336
 one year ago
Best ResponseYou've already chosen the best response.1do you know what the equilibrium constant expression is?

Photon336
 one year ago
Best ResponseYou've already chosen the best response.1wel, \[\frac{ [C]^{a}[D]^{b}}{ [A]^{c}[B]^{d} } = K_{p}\]

korosh23
 one year ago
Best ResponseYou've already chosen the best response.1Actually my teacher have not started that yet. She taught my calss kinetic reactions and kinetic energy

Photon336
 one year ago
Best ResponseYou've already chosen the best response.1what this expression tells us is that we take the concentration of something mol/L for each reactant and raise it to the power of the stoichiometric coefficient that means the number in front of our reactants and products in your balanced reaction. now this is what i believe you need to know: the fact here is that solids and pure liquids aren't included in this expression, because their concentrations don't change very much over time. So gases will always be included in this expression, and I guess maybe some aqueous solutions too. so for our reaction dw:1442777278804:dw

korosh23
 one year ago
Best ResponseYou've already chosen the best response.1@Photon336 , so that means the partial pressure of O2 (g) will affect the reaction rate of the heterogeneous reaction?

Photon336
 one year ago
Best ResponseYou've already chosen the best response.1I believe that's correct; equilibrium would be different though, I think

Photon336
 one year ago
Best ResponseYou've already chosen the best response.1This is an entirely different concept but like say if your reaction were at equilibrium, Increasing/decreasing the pressure wouldn't do anything to the equilibrium. C(s) + O2 > CO2(g) why, because there's the same number of moles on both sides and C(s) doesn't matter.

korosh23
 one year ago
Best ResponseYou've already chosen the best response.1Exactly, same number of moles of gas.

Photon336
 one year ago
Best ResponseYou've already chosen the best response.1Yes @korosh23 exactly Last thing/different concept if you were asked for the rate constant or to determine the rate law something along the lines like k[A][B] = r you cant do this because you would need a chart for the concentrations of A, B. too. hope this helped.

korosh23
 one year ago
Best ResponseYou've already chosen the best response.1Ok, thank you. You are a very good chem tutor.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.