anonymous
  • anonymous
help please! Evaluate the summation of 20 times 0.5 to the n minus 1 power, from n equals 3 to 12.. 9.99 19.95 29.98 39.96
Mathematics
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
\[\sum_{n=3}^{12} 20 \times 0.5^{n-1}\] This is it, right?
anonymous
  • anonymous
yes
anonymous
  • anonymous
@larryboxaplenty

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anonymous
  • anonymous
I can't help you right now, sorry, g2g for a sec someone else can help. I know the answer for forget the shortcut
anonymous
  • anonymous
can someone please help me
Jhannybean
  • Jhannybean
\[\large 20 \cdot \left(0.5^{n-1}\right)\] start with plugging in \(n=3\) and work your way up to \(n=12\) by adding all the values.
Jhannybean
  • Jhannybean
\[\large 20\cdot (0.5^{3-1} + 0.5^{4-1}+0.5^{5-1}+...+0.5^{12-1})\]
welshfella
  • welshfella
or you can use the formula for the sum of a geometric series Sn = a . (1 - r^n) ------ 1 - r
welshfella
  • welshfella
here a = 20*0.5^2 , n = 11 and r = 0.5
anonymous
  • anonymous
so would i get 9.99 as the answer
anonymous
  • anonymous
@welshfella
welshfella
  • welshfella
yes
anonymous
  • anonymous
thank you
welshfella
  • welshfella
yw

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