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anonymous
 one year ago
Find the upperbound for the summation, such that:
(using the lowest possible integer)
anonymous
 one year ago
Find the upperbound for the summation, such that: (using the lowest possible integer)

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amistre64
 one year ago
Best ResponseYou've already chosen the best response.1it feels like there is something missing in the post

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\sum_{n=4200}^{x}n ^{1.5} \ge 1.0 \times 10^{8}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0not sure if possible. I could solve it if it was something like 5n

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1does this have anything to do with a remainder thrm?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I want to solve it for a game. Putting in random numbers, the closest integer I could get to have the same as close as possible to 100 million is 4563

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0*starting at 4220 >_>

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Wolfram gives me weird zeta functions or harmonic numbers

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0100 million, so 10^8 (if I did that right)

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1\[\int_{4200}^{x}x^{1.5}dx=x^{2.5}/2.5(4200)^{2.5}/2.5\] \[x^{2.5}/2.5(4200)^{2.5}/2.5=10^8\] \[x^{2.5}(4200)^{2.5}=2.5*10^8\] \[x^{2.5}=(4200)^{2.5}+2.5*10^8\] \[x=((4200)^{2.5}+2.5*10^8\])^{1/}

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1ugh ... firefox crashed at the end of that

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1\[x=((4200)^{2.5}+2.5*10^8)^{1/2.5}=4545.ddd\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I tried integrals, I must have done it wrong.

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1http://www.wolframalpha.com/input/?i=sum%28n%3D4200+to+4545%29n^%281.5%29

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1letting x=4545 seems to be fair

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh, I see what I did wrong. Thank you :D
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