Jhannybean
  • Jhannybean
Determine whether the value of the gas constant R would be: a) higher, b) lower, c) cause no change if: Zn(s) contains contaminants that are insoluble with HCl solution (hint: follow a setup for the calculation of R to see the effect of each error)
Chemistry
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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Jhannybean
  • Jhannybean
@Photon336
Jhannybean
  • Jhannybean
So I started with the reaction: \(\sf Zn~(s) ~+~ HCl ~(aq)~\rightarrow ~ZnCl_2~(aq)~+~H_2~(g)~\) the ideal gas law only applies to gasses, therefore setting up my ratio for R, I get, \(\sf R=\dfrac{P_{H_2}V_{H_2}}{n_{H_2}T_{H_2}}\)
Jhannybean
  • Jhannybean
Does the contamination of zinc \(\mathbf {lower}\) the actual amount of zinc reacting with the HCl?

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Jhannybean
  • Jhannybean
\[\sf Zn~(s) ~+~ \color{red}{2}HCl ~(aq)~\rightarrow ~ZnCl_2~(aq)~+~H_2~(g)~\]
anonymous
  • anonymous
Contamination would lower the amount of zinc before the reaction or at the reaction.
Jhannybean
  • Jhannybean
Ohhh, alright!
anonymous
  • anonymous
And they're insoluble with HCl, which leaves a lighter zinc.
Jhannybean
  • Jhannybean
Then how would using a lower amount of zinc effect the volume of \(\sf H_2\) ?
Photon336
  • Photon336
I agree with @Shalante
anonymous
  • anonymous
Not 100% sure though.
anonymous
  • anonymous
I would say Zinc+contaminants+HCl>> Zinc Chloride+Hydrogen gas+contaminants. Mass of Contaminants before=mass of contaminants after.
Jhannybean
  • Jhannybean
Oh... the way I calculated it I think I might have done something wrong. I took the mass of zinc I had measured out, and converted that into moles, used PV=nRT to find the volume with the respective moles f zinc from the measured amount. Then I compared it to zinc with contaminants, but the mass of zinc with contaminants should have been lower, and not a higher amount I think.
Jhannybean
  • Jhannybean
So.. i'll write out what I did.
anonymous
  • anonymous
PV=nRT on a solid? (zinc)
Jhannybean
  • Jhannybean
\[\text{mass of zinc w/o contamin.} =0.1901~g~Zn\]\[\sf ~P_{H_2} =~0.961~atm~\\ V_{H_2}~=~?~\\ n_{H_2} = 0.1901~g~Zn ~\times~\frac{1~mol~Zn}{65.39~g~Zn} = 0.002907~mol~Zn \]\[\sf PV=nRT \\ (0.961~ atm)V_{H_2} =~ (0.002907~ mol)\left(\frac{0.0821~L ~atm}{~ mol~ K}\right) (295~K) \\ V_{H_2} = 0.0732~ L\]
Jhannybean
  • Jhannybean
Ack. nvm. I had to change to moles of \(H_2\)
Jhannybean
  • Jhannybean
\[\sf ~P_{H_2} =~0.961~atm~\\ V_{H_2}~=~?~\\ n_{H_2} = 0.1901~g~Zn ~\times~\frac{1~mol~Zn}{65.39~g~Zn}~\times~\frac{1~mol~H_2}{1~mol~Zn } = 0.002097 ~mol~H_2 ~\]
Jhannybean
  • Jhannybean
I did the same thing by increasing the g of zinc with contaminants, but i think that is wrong to do because it will give me a higher value volume of H2.
anonymous
  • anonymous
Grams of zinc decreases with contaminants . That is my opinion.
anonymous
  • anonymous
But zinc can be a contaminant lol. If zinc contains contaminants, it cant have more zinc. Either it stays the same or decreases. Thats what I think.
Jhannybean
  • Jhannybean
yeah, the correct answer was that it \(\mathbf {lowered}\) the value of the gas constant, which would only make sense if the \(\mathbf{volume}\) of the \(\sf H_2\) gas was \(\mathbf{decreased}\) due to the \(\mathbf{decrease}\) in moles of \(\sf H_2\) produced by a \(\mathbf{decrease}\) in the moles of contaminated Zn.
anonymous
  • anonymous
Oh yeah, I mentioned that earlier and photon agree. Because I think contaminant is in some case can decrease an element by removing it through chemical reaction. Just like how soap kills bacteria, but contamination is the opposite.
anonymous
  • anonymous
I only studied contamination in groundwater and the amount of contamination that adds up to it makes the water undrinkable due to lack to hydrogen and oxygen.
anonymous
  • anonymous
I didnt realize my drawing was cut out. I used conservation of mass on a table earlier, but it was cut off. I didnt realize. It showed that the grams of hydrogen gas decrease in mass with contaminants
Jhannybean
  • Jhannybean
Ahh I see I see. It makes sense now!
Jhannybean
  • Jhannybean
Thank you @Shalante :)
Jhannybean
  • Jhannybean
I might have some other questions later!
anonymous
  • anonymous
Ok, I'll check it out later. See you soon.
Jhannybean
  • Jhannybean
^^

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