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anonymous
 one year ago
Determine whether the value of the gas constant R would be:
a) higher, b) lower, c) cause no change
if: Zn(s) contains contaminants that are insoluble with HCl solution
(hint: follow a setup for the calculation of R to see the effect of each error)
anonymous
 one year ago
Determine whether the value of the gas constant R would be: a) higher, b) lower, c) cause no change if: Zn(s) contains contaminants that are insoluble with HCl solution (hint: follow a setup for the calculation of R to see the effect of each error)

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So I started with the reaction: \(\sf Zn~(s) ~+~ HCl ~(aq)~\rightarrow ~ZnCl_2~(aq)~+~H_2~(g)~\) the ideal gas law only applies to gasses, therefore setting up my ratio for R, I get, \(\sf R=\dfrac{P_{H_2}V_{H_2}}{n_{H_2}T_{H_2}}\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Does the contamination of zinc \(\mathbf {lower}\) the actual amount of zinc reacting with the HCl?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\sf Zn~(s) ~+~ \color{red}{2}HCl ~(aq)~\rightarrow ~ZnCl_2~(aq)~+~H_2~(g)~\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Contamination would lower the amount of zinc before the reaction or at the reaction.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0And they're insoluble with HCl, which leaves a lighter zinc.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Then how would using a lower amount of zinc effect the volume of \(\sf H_2\) ?

Photon336
 one year ago
Best ResponseYou've already chosen the best response.0I agree with @Shalante

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Not 100% sure though.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I would say Zinc+contaminants+HCl>> Zinc Chloride+Hydrogen gas+contaminants. Mass of Contaminants before=mass of contaminants after.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh... the way I calculated it I think I might have done something wrong. I took the mass of zinc I had measured out, and converted that into moles, used PV=nRT to find the volume with the respective moles f zinc from the measured amount. Then I compared it to zinc with contaminants, but the mass of zinc with contaminants should have been lower, and not a higher amount I think.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So.. i'll write out what I did.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0PV=nRT on a solid? (zinc)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\text{mass of zinc w/o contamin.} =0.1901~g~Zn\]\[\sf ~P_{H_2} =~0.961~atm~\\ V_{H_2}~=~?~\\ n_{H_2} = 0.1901~g~Zn ~\times~\frac{1~mol~Zn}{65.39~g~Zn} = 0.002907~mol~Zn \]\[\sf PV=nRT \\ (0.961~ atm)V_{H_2} =~ (0.002907~ mol)\left(\frac{0.0821~L ~atm}{~ mol~ K}\right) (295~K) \\ V_{H_2} = 0.0732~ L\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ack. nvm. I had to change to moles of \(H_2\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\sf ~P_{H_2} =~0.961~atm~\\ V_{H_2}~=~?~\\ n_{H_2} = 0.1901~g~Zn ~\times~\frac{1~mol~Zn}{65.39~g~Zn}~\times~\frac{1~mol~H_2}{1~mol~Zn } = 0.002097 ~mol~H_2 ~\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I did the same thing by increasing the g of zinc with contaminants, but i think that is wrong to do because it will give me a higher value volume of H2.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Grams of zinc decreases with contaminants . That is my opinion.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0But zinc can be a contaminant lol. If zinc contains contaminants, it cant have more zinc. Either it stays the same or decreases. Thats what I think.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeah, the correct answer was that it \(\mathbf {lowered}\) the value of the gas constant, which would only make sense if the \(\mathbf{volume}\) of the \(\sf H_2\) gas was \(\mathbf{decreased}\) due to the \(\mathbf{decrease}\) in moles of \(\sf H_2\) produced by a \(\mathbf{decrease}\) in the moles of contaminated Zn.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh yeah, I mentioned that earlier and photon agree. Because I think contaminant is in some case can decrease an element by removing it through chemical reaction. Just like how soap kills bacteria, but contamination is the opposite.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I only studied contamination in groundwater and the amount of contamination that adds up to it makes the water undrinkable due to lack to hydrogen and oxygen.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I didnt realize my drawing was cut out. I used conservation of mass on a table earlier, but it was cut off. I didnt realize. It showed that the grams of hydrogen gas decrease in mass with contaminants

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ahh I see I see. It makes sense now!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thank you @Shalante :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I might have some other questions later!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok, I'll check it out later. See you soon.
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