anonymous
  • anonymous
Explain how you get the answer PLease, i know how to get it and i know the process i just keep getting the wrong answer
Geometry
schrodinger
  • schrodinger
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anonymous
  • anonymous
The Midpoint UV is (5, -11). The coordinates of one endpoint are U(3,5). What is the coordinate of the endpoin V.
Nnesha
  • Nnesha
the formula for midpoint is \[\huge\rm (\frac{ x_1+x_2 }{ 2 } , \frac{ y_1+y_2 }{ 2 })\]given is (x_1 ,y_1) order pair and midpoint (x,y) we can separate both x's and y's \[\large\rm \frac{ x_1+x_2 }{ 2 }=(x-coordinate ~of~midpoint)\] \[\large\rm \frac{ y_1 +y_2 }{ 2 }=(y-coordinate ~of ~midpoint)\] replace (x_1 ,y_1) with the given end point
anonymous
  • anonymous
So would x_1 and y_1 be the midpoint and x_2 and y_2 the endpoint or the other way around?

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Nnesha
  • Nnesha
no (x_1 ,y_1) is the endpoint (3,5)
Nnesha
  • Nnesha
you have to solve for x_2 and y_2
anonymous
  • anonymous
Oh! Okay
Nnesha
  • Nnesha
like to find x-coordinate of 2nd endpoint \[\large\rm \frac{ x_1+x_2 }{ 2 }=(x-coordinate ~of~midpoint)\] \[\large\rm \frac{ 3+x_2 }{ 2 }=5\] now solve for x_2
anonymous
  • anonymous
7?
Nnesha
  • Nnesha
yes right you can check your work \[\frac{ 3+7 }{ 2 }\] if you get 5 then yes ofc it's right bec the midpoint (5,-11) is given
anonymous
  • anonymous
so what would the other endpoint be?
Nnesha
  • Nnesha
we got the x-coordinate now find y-coordinate
Nnesha
  • Nnesha
\[\large\rm \frac{ y_1 +y_2 }{ 2 }=(y-coordinate ~of ~midpoint)\]
anonymous
  • anonymous
5+y_2/2=-11?
Nnesha
  • Nnesha
yes right!
anonymous
  • anonymous
-27?
Nnesha
  • Nnesha
yes right
anonymous
  • anonymous
so 7, -27?
Nnesha
  • Nnesha
yep
anonymous
  • anonymous
Thank you so much!
Nnesha
  • Nnesha
np :=) just an advice the drawing in ur pfp is really good you should post that in design if youdrw that pic
anonymous
  • anonymous
Thank you hahah

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