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anonymous

  • one year ago

Explain how you get the answer PLease, i know how to get it and i know the process i just keep getting the wrong answer

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  1. anonymous
    • one year ago
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    The Midpoint UV is (5, -11). The coordinates of one endpoint are U(3,5). What is the coordinate of the endpoin V.

  2. Nnesha
    • one year ago
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    the formula for midpoint is \[\huge\rm (\frac{ x_1+x_2 }{ 2 } , \frac{ y_1+y_2 }{ 2 })\]given is (x_1 ,y_1) order pair and midpoint (x,y) we can separate both x's and y's \[\large\rm \frac{ x_1+x_2 }{ 2 }=(x-coordinate ~of~midpoint)\] \[\large\rm \frac{ y_1 +y_2 }{ 2 }=(y-coordinate ~of ~midpoint)\] replace (x_1 ,y_1) with the given end point

  3. anonymous
    • one year ago
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    So would x_1 and y_1 be the midpoint and x_2 and y_2 the endpoint or the other way around?

  4. Nnesha
    • one year ago
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    no (x_1 ,y_1) is the endpoint (3,5)

  5. Nnesha
    • one year ago
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    you have to solve for x_2 and y_2

  6. anonymous
    • one year ago
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    Oh! Okay

  7. Nnesha
    • one year ago
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    like to find x-coordinate of 2nd endpoint \[\large\rm \frac{ x_1+x_2 }{ 2 }=(x-coordinate ~of~midpoint)\] \[\large\rm \frac{ 3+x_2 }{ 2 }=5\] now solve for x_2

  8. anonymous
    • one year ago
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    7?

  9. Nnesha
    • one year ago
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    yes right you can check your work \[\frac{ 3+7 }{ 2 }\] if you get 5 then yes ofc it's right bec the midpoint (5,-11) is given

  10. anonymous
    • one year ago
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    so what would the other endpoint be?

  11. Nnesha
    • one year ago
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    we got the x-coordinate now find y-coordinate

  12. Nnesha
    • one year ago
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    \[\large\rm \frac{ y_1 +y_2 }{ 2 }=(y-coordinate ~of ~midpoint)\]

  13. anonymous
    • one year ago
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    5+y_2/2=-11?

  14. Nnesha
    • one year ago
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    yes right!

  15. anonymous
    • one year ago
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    -27?

  16. Nnesha
    • one year ago
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    yes right

  17. anonymous
    • one year ago
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    so 7, -27?

  18. Nnesha
    • one year ago
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    yep

  19. anonymous
    • one year ago
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    Thank you so much!

  20. Nnesha
    • one year ago
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    np :=) just an advice the drawing in ur pfp is really good you should post that in design if youdrw that pic

  21. anonymous
    • one year ago
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    Thank you hahah

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