Identify the graph f'(x) from the graph f(x)?
(posting picture below)

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- anonymous

Identify the graph f'(x) from the graph f(x)?
(posting picture below)

- schrodinger

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- anonymous

I just need help with #42

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- anonymous

random medal

- zepdrix

On the right side of x=0,
notice that it's simply the line y=x.
It has a constant slope of m=1.
So our derivative function should be a constant value.
y'=1 for x>0

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- zepdrix

Which is a horizontal line.

- anonymous

y=x^2

- anonymous

y=x^2

- zepdrix

|dw:1442789065985:dw|

- anonymous

So you're just matching the slopes?

- zepdrix

Ya the derivative function gets its value from the slope of the function at every point.
If that makes sense :o

- zepdrix

Yes, you're matching what the slope is doing, with a new shape.

- anonymous

Okay, so that's why 39 and 42 have the same answer. That makes sense.

- zepdrix

42 is not the same! :) close though

- zepdrix

I only drew half of the function.

- zepdrix

Notice that in 39, the slope stays the same everywhere, it's just a straight line.
The slope is constant m=1 everywhere.
So the derivative function will be a constant f'=1 everywhere.
In 42, we still have to deal with the other side of the V.
Notice that it's a different line segment.
This line has negative slope, see how it's tilted down?

- anonymous

Oh so it'd be C!

- anonymous

Since x=-1 on one side and x=1 on the other

- zepdrix

Ah good! :)

- anonymous

Thank you! This makes more sense now.

- anonymous

i see

- anonymous

whoops

- zepdrix

I'm still confused why these guys were posting x^2 lol

- anonymous

I dunno. Maybe they were thinking about the type of graph rather than the slope?

- zepdrix

perhaps :3

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