anonymous
  • anonymous
Identify the graph f'(x) from the graph f(x)? (posting picture below)
Mathematics
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anonymous
  • anonymous
Identify the graph f'(x) from the graph f(x)? (posting picture below)
Mathematics
schrodinger
  • schrodinger
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anonymous
  • anonymous
I just need help with #42
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anonymous
  • anonymous
random medal
zepdrix
  • zepdrix
On the right side of x=0, notice that it's simply the line y=x. It has a constant slope of m=1. So our derivative function should be a constant value. y'=1 for x>0

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zepdrix
  • zepdrix
Which is a horizontal line.
anonymous
  • anonymous
y=x^2
anonymous
  • anonymous
y=x^2
zepdrix
  • zepdrix
|dw:1442789065985:dw|
anonymous
  • anonymous
So you're just matching the slopes?
zepdrix
  • zepdrix
Ya the derivative function gets its value from the slope of the function at every point. If that makes sense :o
zepdrix
  • zepdrix
Yes, you're matching what the slope is doing, with a new shape.
anonymous
  • anonymous
Okay, so that's why 39 and 42 have the same answer. That makes sense.
zepdrix
  • zepdrix
42 is not the same! :) close though
zepdrix
  • zepdrix
I only drew half of the function.
zepdrix
  • zepdrix
Notice that in 39, the slope stays the same everywhere, it's just a straight line. The slope is constant m=1 everywhere. So the derivative function will be a constant f'=1 everywhere. In 42, we still have to deal with the other side of the V. Notice that it's a different line segment. This line has negative slope, see how it's tilted down?
anonymous
  • anonymous
Oh so it'd be C!
anonymous
  • anonymous
Since x=-1 on one side and x=1 on the other
zepdrix
  • zepdrix
Ah good! :)
anonymous
  • anonymous
Thank you! This makes more sense now.
anonymous
  • anonymous
i see
anonymous
  • anonymous
whoops
zepdrix
  • zepdrix
I'm still confused why these guys were posting x^2 lol
anonymous
  • anonymous
I dunno. Maybe they were thinking about the type of graph rather than the slope?
zepdrix
  • zepdrix
perhaps :3

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