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anonymous

  • one year ago

Identify the graph f'(x) from the graph f(x)? (posting picture below)

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  1. anonymous
    • one year ago
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    I just need help with #42

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  2. anonymous
    • one year ago
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    random medal

  3. zepdrix
    • one year ago
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    On the right side of x=0, notice that it's simply the line y=x. It has a constant slope of m=1. So our derivative function should be a constant value. y'=1 for x>0

  4. zepdrix
    • one year ago
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    Which is a horizontal line.

  5. anonymous
    • one year ago
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    y=x^2

  6. anonymous
    • one year ago
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    y=x^2

  7. zepdrix
    • one year ago
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    |dw:1442789065985:dw|

  8. anonymous
    • one year ago
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    So you're just matching the slopes?

  9. zepdrix
    • one year ago
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    Ya the derivative function gets its value from the slope of the function at every point. If that makes sense :o

  10. zepdrix
    • one year ago
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    Yes, you're matching what the slope is doing, with a new shape.

  11. anonymous
    • one year ago
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    Okay, so that's why 39 and 42 have the same answer. That makes sense.

  12. zepdrix
    • one year ago
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    42 is not the same! :) close though

  13. zepdrix
    • one year ago
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    I only drew half of the function.

  14. zepdrix
    • one year ago
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    Notice that in 39, the slope stays the same everywhere, it's just a straight line. The slope is constant m=1 everywhere. So the derivative function will be a constant f'=1 everywhere. In 42, we still have to deal with the other side of the V. Notice that it's a different line segment. This line has negative slope, see how it's tilted down?

  15. anonymous
    • one year ago
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    Oh so it'd be C!

  16. anonymous
    • one year ago
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    Since x=-1 on one side and x=1 on the other

  17. zepdrix
    • one year ago
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    Ah good! :)

  18. anonymous
    • one year ago
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    Thank you! This makes more sense now.

  19. anonymous
    • one year ago
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    i see

  20. anonymous
    • one year ago
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    whoops

  21. zepdrix
    • one year ago
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    I'm still confused why these guys were posting x^2 lol

  22. anonymous
    • one year ago
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    I dunno. Maybe they were thinking about the type of graph rather than the slope?

  23. zepdrix
    • one year ago
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    perhaps :3

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