find the limit as f(g(x)) approaches 1 f(x)= 3/(x-1) g(x)= x^4 I got f(g(x))= 3/(x^4-1) but I need help finding the limit.

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find the limit as f(g(x)) approaches 1 f(x)= 3/(x-1) g(x)= x^4 I got f(g(x))= 3/(x^4-1) but I need help finding the limit.

Mathematics
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There's a vertical asymptote at 1. Have you tried taking the limits from the left and right sides?
on my graph I don't see a left hand limit, but is the right hand limit infinity?
Yes the right is infinity Does your graph look like this?|dw:1442790635351:dw|

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yes wait then from the left isn't the limit negative infinity
right
since the left and right limits aren't the same, the limit does not exist
ohhhh i see. Thanks so much! If you have time, would you mind helping me with another limit question? I'm not very good at limits
sure
find the limit as x approaches 0 of (3x^4 - 6x^3)/(4x^3 + 2x^2)
I'd start this one by factoring to see what cancels out.
okay so I got 3x^3(x-2) / 2x^2(2x+1)
right, and two of the x's in the numerator will cancel the x² in the denominator, and then you can plug in the 0
\[\frac{3x(x-2)}{2(2x+1)}\]
I got 0 as my answer
that's right :)
Thanks a million! You're really a lifesaver!! :D
you're welcome

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