cassieforlife5
  • cassieforlife5
find the limit as f(g(x)) approaches 1 f(x)= 3/(x-1) g(x)= x^4 I got f(g(x))= 3/(x^4-1) but I need help finding the limit.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
There's a vertical asymptote at 1. Have you tried taking the limits from the left and right sides?
cassieforlife5
  • cassieforlife5
on my graph I don't see a left hand limit, but is the right hand limit infinity?
anonymous
  • anonymous
Yes the right is infinity Does your graph look like this?|dw:1442790635351:dw|

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cassieforlife5
  • cassieforlife5
yes wait then from the left isn't the limit negative infinity
anonymous
  • anonymous
right
anonymous
  • anonymous
since the left and right limits aren't the same, the limit does not exist
cassieforlife5
  • cassieforlife5
ohhhh i see. Thanks so much! If you have time, would you mind helping me with another limit question? I'm not very good at limits
anonymous
  • anonymous
sure
cassieforlife5
  • cassieforlife5
find the limit as x approaches 0 of (3x^4 - 6x^3)/(4x^3 + 2x^2)
anonymous
  • anonymous
I'd start this one by factoring to see what cancels out.
cassieforlife5
  • cassieforlife5
okay so I got 3x^3(x-2) / 2x^2(2x+1)
anonymous
  • anonymous
right, and two of the x's in the numerator will cancel the x² in the denominator, and then you can plug in the 0
anonymous
  • anonymous
\[\frac{3x(x-2)}{2(2x+1)}\]
cassieforlife5
  • cassieforlife5
I got 0 as my answer
anonymous
  • anonymous
that's right :)
cassieforlife5
  • cassieforlife5
Thanks a million! You're really a lifesaver!! :D
anonymous
  • anonymous
you're welcome

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