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cassieforlife5
 one year ago
find the limit as f(g(x)) approaches 1
f(x)= 3/(x1) g(x)= x^4
I got f(g(x))= 3/(x^41) but I need help finding the limit.
cassieforlife5
 one year ago
find the limit as f(g(x)) approaches 1 f(x)= 3/(x1) g(x)= x^4 I got f(g(x))= 3/(x^41) but I need help finding the limit.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0There's a vertical asymptote at 1. Have you tried taking the limits from the left and right sides?

cassieforlife5
 one year ago
Best ResponseYou've already chosen the best response.0on my graph I don't see a left hand limit, but is the right hand limit infinity?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes the right is infinity Does your graph look like this?dw:1442790635351:dw

cassieforlife5
 one year ago
Best ResponseYou've already chosen the best response.0yes wait then from the left isn't the limit negative infinity

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0since the left and right limits aren't the same, the limit does not exist

cassieforlife5
 one year ago
Best ResponseYou've already chosen the best response.0ohhhh i see. Thanks so much! If you have time, would you mind helping me with another limit question? I'm not very good at limits

cassieforlife5
 one year ago
Best ResponseYou've already chosen the best response.0find the limit as x approaches 0 of (3x^4  6x^3)/(4x^3 + 2x^2)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'd start this one by factoring to see what cancels out.

cassieforlife5
 one year ago
Best ResponseYou've already chosen the best response.0okay so I got 3x^3(x2) / 2x^2(2x+1)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0right, and two of the x's in the numerator will cancel the x² in the denominator, and then you can plug in the 0

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{3x(x2)}{2(2x+1)}\]

cassieforlife5
 one year ago
Best ResponseYou've already chosen the best response.0I got 0 as my answer

cassieforlife5
 one year ago
Best ResponseYou've already chosen the best response.0Thanks a million! You're really a lifesaver!! :D
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