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blackstreet23

  • one year ago

Sketch the curve in polar coordinates r^2 = 16 sin 2(theta)

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  1. blackstreet23
    • one year ago
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    @Hero @Shalante @IrishBoy123

  2. Hero
    • one year ago
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    It's best to use a polar graph to plot the points

  3. blackstreet23
    • one year ago
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    umm I think i might know what i have to do

  4. blackstreet23
    • one year ago
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    but i just dont know is that is right

  5. blackstreet23
    • one year ago
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    I mean i trying to find the endpoints to just draw a rought sketch

  6. blackstreet23
    • one year ago
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    I got that \[r = +or- (r*\sqrt{2\sin(\theta)}\]

  7. blackstreet23
    • one year ago
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    sorry 4

  8. blackstreet23
    • one year ago
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    4 * root(sin2(theta))

  9. blackstreet23
    • one year ago
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    ?

  10. Hero
    • one year ago
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    https://www.desmos.com/calculator/kqckk5hpar

  11. Hero
    • one year ago
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    The graph is the same for both positive and negative expressions

  12. blackstreet23
    • one year ago
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    ohh ok. I think i get it

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spraguer (Moderator)
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