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blackstreet23
 one year ago
Sketch the curve in polar coordinates
r^2 = 16 sin 2(theta)
blackstreet23
 one year ago
Sketch the curve in polar coordinates r^2 = 16 sin 2(theta)

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blackstreet23
 one year ago
Best ResponseYou've already chosen the best response.0@Hero @Shalante @IrishBoy123

Hero
 one year ago
Best ResponseYou've already chosen the best response.0It's best to use a polar graph to plot the points

blackstreet23
 one year ago
Best ResponseYou've already chosen the best response.0umm I think i might know what i have to do

blackstreet23
 one year ago
Best ResponseYou've already chosen the best response.0but i just dont know is that is right

blackstreet23
 one year ago
Best ResponseYou've already chosen the best response.0I mean i trying to find the endpoints to just draw a rought sketch

blackstreet23
 one year ago
Best ResponseYou've already chosen the best response.0I got that \[r = +or (r*\sqrt{2\sin(\theta)}\]

blackstreet23
 one year ago
Best ResponseYou've already chosen the best response.04 * root(sin2(theta))

Hero
 one year ago
Best ResponseYou've already chosen the best response.0The graph is the same for both positive and negative expressions

blackstreet23
 one year ago
Best ResponseYou've already chosen the best response.0ohh ok. I think i get it
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