## anonymous one year ago if i have a 165.1cm length and 2cm diameter of bamboo, and i want to produce 22cm length, .5cm height, and 2 cm width stick. How many possible output or stick, i will produced in my required L,W and H?

1. TheCatMan

2. anonymous

6 sir

3. anonymous

do yo any idea, can u help me @TheCatMan

4. TheCatMan

is that worded exactly as it is on the work page

5. anonymous

yup,

6. anonymous

check my work and correct me if im wrong,

7. anonymous

for the length, $\frac{ 165.2 cm }{ 22cm } = 8 pcs of length$

8. anonymous

for the width, i will get the circumference of the bamboo, C=piD

9. anonymous

C= 2 pi , then 6.28 will be the answered but im considered this as 7 cm then$\frac{ 7 cm}{ 2cm }= 4pcs$

10. anonymous

likewise, for the thickness or height, $\frac{ 2cm }{ .5cm} =4 pcs$

11. anonymous

then, do you have any idea for my next step ?

12. TheCatMan

sorry my pc froze and you have the right set up

13. TheCatMan

and i need coffee brb

14. anonymous

i dont know what my net step dou u have any idea for the possible output

15. TheCatMan

just put that if it doesn't require simplification

16. anonymous

@mathmate

17. anonymous

is there's any way to solve for the possible output? @TheCatMan

18. TheCatMan

im not the best to ask im not good at math my main thing is science

19. anonymous

ok sir thank you sir for your time :)

20. TheCatMan

im 16 please dont call me sir it makes me feel old

21. mathmate

@melmel

22. mathmate

|dw:1442797622006:dw| Yes, I think the 0.5 cm is the thinkness of the bamboo (about 1/4 of its diameter). So as you did, find the number of pieces $$N_L$$ over the length by dividing 165.1cm by 22cm (reject remainder of division). Then number of pieces $$N_C$$ over the circumference (6.28 divided by 2 cm). The total number of sticks will then be $$N_L*N_C$$.

23. anonymous

@mathmate

24. mathmate

Do you have a question? @melmel