if i have a 165.1cm length and 2cm diameter of bamboo, and i want to produce 22cm length, .5cm height, and 2 cm width stick. How many possible output or stick, i will produced in my required L,W and H?

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if i have a 165.1cm length and 2cm diameter of bamboo, and i want to produce 22cm length, .5cm height, and 2 cm width stick. How many possible output or stick, i will produced in my required L,W and H?

Mathematics
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what grade are you in?
6 sir
do yo any idea, can u help me @TheCatMan

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is that worded exactly as it is on the work page
yup,
check my work and correct me if im wrong,
for the length, \[\frac{ 165.2 cm }{ 22cm } = 8 pcs of length\]
for the width, i will get the circumference of the bamboo, C=piD
C= 2 pi , then 6.28 will be the answered but im considered this as 7 cm then\[\frac{ 7 cm}{ 2cm }= 4pcs\]
likewise, for the thickness or height, \[\frac{ 2cm }{ .5cm} =4 pcs\]
then, do you have any idea for my next step ?
sorry my pc froze and you have the right set up
and i need coffee brb
i dont know what my net step dou u have any idea for the possible output
just put that if it doesn't require simplification
is there's any way to solve for the possible output? @TheCatMan
im not the best to ask im not good at math my main thing is science
ok sir thank you sir for your time :)
im 16 please dont call me sir it makes me feel old
|dw:1442797622006:dw| Yes, I think the 0.5 cm is the thinkness of the bamboo (about 1/4 of its diameter). So as you did, find the number of pieces \(N_L\) over the length by dividing 165.1cm by 22cm (reject remainder of division). Then number of pieces \(N_C\) over the circumference (6.28 divided by 2 cm). The total number of sticks will then be \(N_L*N_C\).
Do you have a question? @melmel

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