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cooltowl
 one year ago
You dissolve the sample of FD&C Red 40 (molar mass 496.4200 g/mol) in enough water to make 250.0 mL of solution. We call this the stock solution.
What is the concentration of the stock solution in terms of molarity?
cooltowl
 one year ago
You dissolve the sample of FD&C Red 40 (molar mass 496.4200 g/mol) in enough water to make 250.0 mL of solution. We call this the stock solution. What is the concentration of the stock solution in terms of molarity?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[Molarity=\frac{ mol solute }{ volume }\] mol solute in grams volume in liters.

cooltowl
 one year ago
Best ResponseYou've already chosen the best response.1so I divide the molar mass or Red 40 by 250 ml?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0FD&C Red 40 is the name of substance being dissolved. 1 sample of it would have 496.420g

cooltowl
 one year ago
Best ResponseYou've already chosen the best response.1how do I get moles of solute?

cooltowl
 one year ago
Best ResponseYou've already chosen the best response.1Never mind I got it the answer. I divided 1.833x10^5/.25

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh, I think you didnt post more information with this question. This is part of a series of questions right?

cooltowl
 one year ago
Best ResponseYou've already chosen the best response.1Yeah Im sorry about that I just realized it when I was trying to solve the problem but thank you. you helped a lot

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0No wonder. Just post information that goes with the question next time. Good luck.

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.0Yeah, seems like some parts were missing.
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