You dissolve the sample of FD&C Red 40 (molar mass 496.4200 g/mol) in enough water to make 250.0 mL of solution. We call this the stock solution. What is the concentration of the stock solution in terms of molarity?

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You dissolve the sample of FD&C Red 40 (molar mass 496.4200 g/mol) in enough water to make 250.0 mL of solution. We call this the stock solution. What is the concentration of the stock solution in terms of molarity?

Chemistry
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\[Molarity=\frac{ mol solute }{ volume }\] mol solute in grams volume in liters.
Molarity in M
so I divide the molar mass or Red 40 by 250 ml?

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FD&C Red 40 is the name of substance being dissolved. 1 sample of it would have 496.420g
how do I get moles of solute?
Never mind I got it the answer. I divided 1.833x10^-5/.25
Oh, I think you didnt post more information with this question. This is part of a series of questions right?
Yeah Im sorry about that I just realized it when I was trying to solve the problem but thank you. you helped a lot
No wonder. Just post information that goes with the question next time. Good luck.
Yeah, seems like some parts were missing.

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