i need help .. please

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i need help .. please

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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1 Attachment
I'm sorry but did they mention any other angle's degree??
no they didnt

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no one likes this kind of geometry do they?
no lol
i dont get it
i am sure it is doable though lets see what we can come up with
okay thanks
let me try to draw it
okay
damn screwed up already, go the sides wrong gotta start over
|dw:1442803070373:dw|
alrighty
|dw:1442803248679:dw|
okay.. how do i figure out the measurements?
now lets fill in the 72 we didn't do that yet
|dw:1442803341238:dw|
now we can find angles RSQ and RQS because the are equal in the internal angles of a triangle add up to 180 we have used up 72 already, that leaves \(180-72=108\) halve of that is \(54\) so each of those must be 54
|dw:1442803491836:dw|
seem reasonable?
yes it does but do we put 54 as the answer or what do we put
54 is the answer to the first two questions
oh okay
now lets fill in another since a line also has 180 degrees we can find \(180-54=126\)
|dw:1442803708556:dw|
okay
that is angle SQP number 4 in your questions
the third and 5th are like before subtract \(126\) from \(180\) then divide by 2
27?
can you help me with another part? @satellite73
yeah 27
you mean there is more? taxing my brain already, but i can look
1 Attachment
ok they are all equal and they all add up to 180 i guess we can solve that with some algebra (i hope)
\[3a+4+6b+19c+3=180\] and \[3a+4=6b=19c+3\]
this is going to suck a bit how is your algebra?
oh my favorite algebra (sarcasm)
okay
we can also write each of the bottom equations in terms of one variable maybe \(b\)
okay okay i kinda get it
so far so good? we have \(a\) in terms of \(b\)
actually i am being a little stupid here, lets work smarter
oh
clear or no? just subtracted is all
i got it
ok now we can solve but before we do that, let me say that i am really stupid tonight
all the sides are the same, so all the angles are the same since they add up to 180, they are all 60
no youre fine
if \(6b=60\) then \(b=10\)
so a b c are 60?
no \(6b=60\) so \(b=10\)
oh okay
and also \[3a+4=60\] so \[3a=56\] making \[a=\frac{54}{3}\]
A - 18?
and finally \[19c+3=60\] so \[19c=57\] making \[c=\frac{57}{19}\]
A=18 sorry
typo there \[3a+4=60\\ 3a=56\\ a=\frac{56}{3}\] it is not a whole number
so a and c arent whole numbers and thats okay
actually c is a whole number
\[57\div 19=3\]
oh okay
only a is not a whole number this was not nearly as hard as it looks, just had to solve 3 equations \[3a+4=60\\ 6b=60\\ 19c+3=60\]
is there more or are we done?
that was it thank you so much !!
yw now i have a question
why are you legendary?
is that a serious question? lol
sorta just a nick name or did you make it up?
nick name
cool lol

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