anonymous
  • anonymous
A student uses the quadratic formula to solve a quadratic equation and determines that one of the solutions is x equals negative seven plus square root of negative 99 end square root. What are the values of a and b if this solution is written in the form x = a + bi, where a and b are real numbers?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
HELP PLEASE
anonymous
  • anonymous
Bit of factoring is all that's required. You are given\[x=-7 + \sqrt{-99}\]Let's do some factoring using the rules of working with radicals.\[x=-7 + \sqrt{99}\sqrt{-1}\]You OK with that so far?
anonymous
  • anonymous
yes

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anonymous
  • anonymous
Good. Now, are you able to simplify \(\sqrt{99}\) ?
anonymous
  • anonymous
3√ 11
anonymous
  • anonymous
right?
anonymous
  • anonymous
Excellent. And do you know what \(\sqrt{-1}\) is?
anonymous
  • anonymous
1
anonymous
  • anonymous
No. The square root of -1 is the imaginary number i. It is referred to in the question. Have you seen it before?
anonymous
  • anonymous
oh yes!
anonymous
  • anonymous
OK. So now your question looks like\[x=-7 + \sqrt{99}\sqrt{-1}\]\[x=-7+3\sqrt{11}i\]Compare this with\[x=a+bi\]What are the values of a and b?
anonymous
  • anonymous
a=-7 b=3√11
anonymous
  • anonymous
Fantastic. Good job!
anonymous
  • anonymous
Thank you sooo much :))))
anonymous
  • anonymous
You're welcome.

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