anonymous
  • anonymous
NEED HELP ASAP! WILL GIVE MEDAL! What is the area of the figure? https://static.k12.com/calms_media/media/381000_381500/381290/2/57636c518573add2dac05c3e75e551672caed213/53018_question.jpg
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
after u solve this problem will u stay 2 help?
Jhannybean
  • Jhannybean
|dw:1442798699321:dw|
anonymous
  • anonymous
ok?

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Jhannybean
  • Jhannybean
|dw:1442798822656:dw|
Jhannybean
  • Jhannybean
What does the ? equal to
anonymous
  • anonymous
12-8=4
Jhannybean
  • Jhannybean
Good.
Jhannybean
  • Jhannybean
|dw:1442798869132:dw|
Jhannybean
  • Jhannybean
Now , we're finding \(\large A_{\text{Big rectangle - little rectangle}} \)
anonymous
  • anonymous
ok?
Jhannybean
  • Jhannybean
Start by finding \(A_{\text{big rectangle}}= l\cdot w = 12 \cdot 13 = ~?\)
anonymous
  • anonymous
it is 156
Jhannybean
  • Jhannybean
Alright, and \(\large A_{\text{little rectangle}} = l\cdot w = 7 \cdot 4 = ~?\)
anonymous
  • anonymous
28.
Jhannybean
  • Jhannybean
\[\large A_{\text{big rectangle - little rectangle}} = 156 - 28 = ~?\]
anonymous
  • anonymous
124
Jhannybean
  • Jhannybean
There you go
anonymous
  • anonymous
thxs plz stay 2 help!
Jhannybean
  • Jhannybean
wait a minute.
Jhannybean
  • Jhannybean
\[156 - 28 \ne 124\]
anonymous
  • anonymous
huh?
anonymous
  • anonymous
oh 128!
Jhannybean
  • Jhannybean
\[\large \checkmark\]
Jhannybean
  • Jhannybean
steps make sense to you, @Yuna123 ?
anonymous
  • anonymous
yup
anonymous
  • anonymous
Which quadrilateral names apply to the figure? Choose all answers that are correct. A. square B. rhombus C. parallelogram D. rectangle https://static.k12.com/calms_media/media/1481000_1481500/1481183/2/8513a0a4286b5363087b2927c62f637580f451ed/MS_IMA_03_12_lesson_manuscript_UNIT_CHECKPOINT_Art_04.jpg
anonymous
  • anonymous
please hurry!
Jhannybean
  • Jhannybean
Are you taking a test?
anonymous
  • anonymous
yes
Jhannybean
  • Jhannybean
then sorry, I cannot help you any further.
anonymous
  • anonymous
what?
anonymous
  • anonymous
ok then bye i guess...
anonymous
  • anonymous
plz help with second question
Jhannybean
  • Jhannybean
You're violating OS CoC. Cheating is impermissible.
anonymous
  • anonymous
oh ok
anonymous
  • anonymous
plz help!

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